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Morgarella [4.7K]
3 years ago
5

If you are transported to a planet that has the same mass as Earth, but is larger in size, how would this affect your weight whe

n standing on the planet’s surface? Explain your answer.
Physics
1 answer:
son4ous [18]3 years ago
4 0

Answer:

The weight will be smaller than on Earth.

Explanation:

We call weight, to the product of the mass times the acceleration produced on this mass, due to the Universal law of gravitation.

This acceleration can be obtained applying Newton’s 2nd Law to the gravitational attractive force, as follows:

Fg = G m1m2 / (r12)2 = m1* a → a= G m2 / (r12)2 =g

If we take a planet with the same mass, but a larger size, this means that the distance, from the planet’s surface to the center, will be larger also.

As the gravitational attraction is inversely proportional to the square of the distance, this means that the acceleration caused by this force, will be smaller than on Earth.

As the mass is an universal constant, this means that the weight (as measured on a scale as the normal force) will be smaller also.

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In the absence of an electric field, a radioactive beam strikes a fluorescent screen at a single point. When an electric field i
leonid [27]

Answer: Beta, alpha and gamma ray

Explanation: The component being deflected to the positive side is the beta radiation because it is negatively charged and thus is attracted by the positive terminal of the Electric Field.

The component being deflected to the negative side is the alpha radiation, it's is positively charged and thus being attracted by the negative part of the Electric Field.

The component that went straight down without deflection is the gamma radiation. It is neutral and possess no charge and thus is not deflected.

4 0
3 years ago
Read 2 more answers
The Hall effect can be used to calculate the charge-carrier number density in a conductor. If a conductor carrying a current of
goldfiish [28.3K]

Answer:

6.6*10^{27}e/m^3

Explanation:

When we are dealing with Hall voltage, it is necessary to have the values of the current, the magnetic field, the length, the area and the number of carriers at hand. The Hall voltage equation is given by,V_h = \frac{iB}{neL}

Where,

i= current

B= Magnetic field

L = Length

n = number of charge carriers

e= charge of a electron

We need replace and solve for n,

n= \frac{iB}{V_h e L}

n= \frac{2*1.2}{4.5*10^{-6}*5^10^{-3}*1.6*10^{-19}}

n= 6.6*10^{27}electron.m^{-3}

Therefore the density of charge carrier is 6.6*10^{27}e/m^3

5 0
4 years ago
you record the length of different people's feet is this an example of a controlled experiment true or false
never [62]
False you cant control the size of feet
5 0
3 years ago
Negatively charged particles that orbit the nucleus of an atom are _________. A. electrons B. protons C. neutrons
julsineya [31]

negativily chtarge particles are electron

5 0
4 years ago
The engine that moves the cables for the San Francisco cable cars delivers 390.3 kW of power for each line. How long does it tak
Musya8 [376]

Answer:

It would take 16.7 s for the work to be done by the engine.

Explanation:

From the question, given: Power = 390.3 kW

                                           Work to be done = 6.5 x 10^{6} J

But, power and work done with respect to time, has a relationship of:

Power = \frac{work done}{time}

So that,

time = \frac{work done}{Power}

Thus,

time  = \frac{6.5*10^{6} }{390.3*10^{3} }

       = 16.6539

time = 16.7 s

Time required is 16.7 seconds.

Thus, it would take 16.7 s for the work to be done by the engine.

5 0
3 years ago
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