Which situation could be represented by the integer -10?

Please help me i will mark as brainliest

Bingel [31]

6. P = 2
Q = -5

7. C = -1

8. K = 3

9. A) y = 2x + 2
B) y = -3x + 5
C) y = 0x + -5

10. Y = 5x + -18

11. A)
i) (5, 0)
ii) (0, 5)

B) y = -1x + 0

3 0

2 years ago

Find the mean of the data set shown below. Round to the nearest tenth, if necessary. This Week’s High Temperatures (°F) 29, 38,

malfutka [58]

Answer:

The answer is 44.7, because you have to add up all of the numbers then divide by how many numbers there are.

6 0

1 year ago

Worth 60 points

alex41 [277]

Answer:

Line y = -x + 2 intersects line y = 3x + 1

Step-by-step explanation:

The solution to a system of equations is the point at which the two lines intersect. To find this point, first equate the equations and solve for x:

$\begin{aligned}y & = y\\-x + 2 & = 3x + 1\\-x+2+x & = 3x+1+x\\2 & = 4x + 1\\2-1 & =4x+1-1\\1 &=4x\\x & =\dfrac14\end{aligned}$

Substitute the found value of x into one of the equations, and solve for y:

$y=3\left(\dfrac14\right)+1=\dfrac74$

Therefore, the solution to the system of equations (the point at which the two lines intersect) is:

$\left(\dfrac14,\dfrac74\right)$

So the description that best describes the solution to the system of equations is:

Line y = -x + 2 intersects line y = 3x + 1

3 0

1 year ago

Find the sum. 2x^2 +26x+ 156=0

Mila [183]

Answer:

-13

Step-by-step explanation:

2x²+26x+156=0

x²+13x+78=0

x²+13x=-78

x²+13x+169/4=-143/4

(x+13/2)²=-143/4

x+13/2=(i√143)/2 or x+13/2=-(i√143)/2

x=(i√143)/2-13/2 or x=-(i√143)/2-13/2

(i√143)/2-13/2+(-(i√143)/2)-13/2=(i√143-13-i√143-13)/2=-26/2=-13

5 0

3 years ago

Read 2 more answers

Suppose you are climbing a hill whose shape is given by the equation z = 1400 − 0.005x2 − 0.01y2, where x, y, and z are measured

Anarel [89]

Answer: You start to ascend

Explanation:

Since you are walking due south and the positive y-axis points north, the y-coordinate decreases.

Let

$y'$ = y-coordinate after walking due south
$z'$ = z-coordinate (or the height) after walking due south

So, the point where you stand after walking due south has a coordinate of $(100, y', z')$ . Moreover,

$z' = 1,400 - 0.05(100)^2 - 0.01(y')^2
\\ \boxed{z' = 1350 - 0.01(y')^2}$

Since the y-coordinate decreases after walking due south and $z' = 1350 - 0.01(y')^2$ ,

$y' \leq 120\\ \Rightarrow (y')^2 \leq 120^2 = 14,400\\ \Rightarrow -0.01(y')^2 \geq -0.01(14,400) = -144\\ \Rightarrow z' = 1,350 - 0.01(y')^2 \geq 1,350 - 0.01(14,400) = 1,206\\ \Rightarrow \boxed{z' \geq 1,206}$

So, the height after walking due south exceeds 1,206 meters, which is the previous height before walking due south. Therefore, if you walk due south from point with coordinates (100, 120, 1206), you are ascending.

5 0

3 years ago