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vova2212 [387]
3 years ago
15

What is the standard enthalphy change ΔHo, for the reaction represented above? (ΔHof of C2H2(g) is 230 kJ mol-1; (ΔHof of C6H6(g

) is 83 kJ mol-1;)
Chemistry
1 answer:
wolverine [178]3 years ago
6 0

Answer:

-608KJ/mol

Explanation:

3 C2H2(g) -> C6H6(g)

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= ΔHC6H6 - 3ΔHC2H2

ΔHrxn = 83 - 3(230)

ΔHrxn = -608

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"the osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant
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Answer: -

The concentration is 0.91 mol/ L

Explanation: -

The osmotic pressure = 23 atm

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We know the formula

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Plugging in the values

23 atm = molar concentration x 0.08206 L atm mol⁻¹ K⁻¹ x 309 K

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8 0
3 years ago
Read 2 more answers
How many moles of NaCl are produced if 239.7 grams of Na2S reacts with plenty of AlCl3?
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Answer:

6.142 moles of NaCl

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Next, we determine the number of mole in 239.7 g of Na2S. This is illustrated below:

Mass mass of Na2S = 78.048g/mol

Mass of Na2S = 239.7g

Number of mole Na2S =..?

Mole = Mass /Molar Mass

Number of mole Na2S = 239.7/78.048 = 3.071 moles

Finally, we can obtain the number of mole of NaCl produced from the reaction as follow:

From the balanced equation above,

3 moles of Na2S reacted to produce 6 moles of NaCl.

Therefore, 3.071 moles of Na2S will react to produce = (3.071 x 6)/3 = 6.142 moles of NaCl

3 0
3 years ago
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