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Georgia [21]
4 years ago
15

How many grams of dry nh4cl need to be added to 2.00 l of a 0.600 m solution of ammonia, nh3, to prepare a buffer solution that

has a ph of 8.74? kb for ammonia is 1.8×10−5?

Chemistry
1 answer:
Brrunno [24]4 years ago
8 0
Nh4cl = 117.165 gram ( solution is attached )

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Which order shows the materials having the highest to lowest temperature after 15 minutes of being under the lamps?
diamong [38]

Answer:

The answer to the question is

<h2>A. Air, Soil, Sand, Water</h2>

Explanation:

8 0
4 years ago
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What is the volume occupied by 48.0 g of ouzo, which has a density of 0.940 g/mL?45.1 mL51.1 mL37.0 mL24.5 mL
satela [25.4K]

Density:

The density of a substance is equal to the ratio of its mass and volume. In general we can say the density of a substance is mass per unit volume.

Density = mass in g / volume in cubic cm or ml

Given that  

Density = 0.940 g/ ml

Mass = 48.0 g

Therefore,  

Volume = mass/ density  

= 48.0 g/  0.940 g/ ml

= 51 ml  

Thus the correct answer is 51 ml  


4 0
3 years ago
Calculate the no. of moles in 25gm of calcium phosphate <br><br>Plz Fast Urgent
madreJ [45]

Answer:

0.162 mol

Explanation:

n=m/M

M= 20*3 + 15*2 + 8*4*2

M=154 g/mol

n=25g/154g/mol

n=0.162 mol

7 0
3 years ago
Calculate the change in the standard entropy of the system, delta s degree for the synthesis of ammonia from N_2(g) and H_2(g) a
Svet_ta [14]

Answer:

\Delta S^{0} for the reaction is -198.762 J/K

Explanation:

N_{2}(g)+3H_{2}(g)\rightarrow 2NH_{3}(g)

Standard change in entropy for the system (\Delta S^{0}) is given by-

\Delta S^{0}=[2moles\times S^{0}(NH_{3})_{g}]-[1mole\times S^{0}(N_{2})_{g}]-[3\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Here S^{0}(NH_{3})_{g}=192.45J/(K.mol), S^{0}(N_{2})_{g}=191.61J/(K.mol) and S^{0}(H_{2})_{g}=130.684J/(K.mol)

So, \Delta S^{0}=[2\times 192.45]-[1\times 191.61]-[3\times 130.684]J/K=-198.762J/K

3 0
3 years ago
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3
IgorC [24]

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

5 0
3 years ago
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