Plzzzzzzzzzzzzzzzz help
1 answer:
You might be interested in
The mass percent of sulfurous acid in the new solution : 38.9%
<h3>Further explanation</h3><em>In a container you have 800 g of a 35% by mass solution of sulfurous acid, from which 80 ml of water evaporates. What is the mass percent of sulfurous acid in the new solution? data: density of water is 1g / ml.</em>
<em />
solution 1
composition :
- 35% acid :
- water :
solution 2(new solution)
composition :
- water
- Total mass of new solution after water evaporated
- %mass of acid in a new solution
Answer:
Explanation:
<u>Given Data:</u>
Volume = v = 1.12 dm³ = 1.12 L
Density of nitrogen at STP = D = 1.25 g / L
Molar mass = M = 14 * 2 = 28 g / mol
Avogadro's Number = = 6.023 * 10²³ mol⁻¹
<u>Required:</u>
No. of molecules = ?
<u>Formula:</u>
<u>Solution:</u>
No. of molecules = (1.25*1.12) / 28 * (6.023 * 10²³)
No. of molecules = ( 1.4 / 28 ) * 6.023 * 10²³
No. of molecules = 0.05 * 6.023 * 10²³
No. of molecules = 0.3 * 10²³
No. of molecules = 3 * 10²² molecules
Hope this helped!
<h3>~AH1807</h3>