<h2>Plasma is most likely inflence by - Option C</h2>
This plasma is most likely influenced by magnetic and electric fields. The massive positively charged ions which are influenced the lighter electrons than replace the ions to keep charge impartiality.
Therefore electric field influence the plasma. The movement of charged particles identical to a magnetic field line is not influenced. Plasma contains charged particles which are positive nuclei and negative electrons which can be molded and restricted by magnetic forces.
Alike iron filings in the closeness of a magnet, bits in the plasma will ensue magnetic field lines.
Always use least amount of sig figs possible. So this 9.7 would be (answer): 2 sig figs
Hydrogen gas and oxygen gas react to form liquid water according to the following equation:
2H₂ + O₂ → 2H₂O
a. Converting our given masses of each gas to moles, we have:
(25 g H2)/(2 × 1.008 g/mol) = 12.4 mol H2; and
(25 g O2)/(2 × 15.999 g/mol) = 0.781 mol O2.
From the equation, two moles of H2 react with every one mole of O2. To fully react with 12.4 moles of H2, as we have here, one would need 6.2 moles of O2, which is far more than what we're actually given. Thus, the oxygen is our limiting reactant, and as such it will be the first reactant to run out.
b. Since O2 is our limiting reactant, we use it for determining how much product, in this case, H2O, is produced. From the equation, there is a 1:1 molar ratio between O2 and H2O. Thus, the number of moles of H2O produced will be the same as the number of moles of O2 that react: 0.781 moles of H2O. The mass of water produced would be (0.781 mol H2O)(18.015 g/mol) ≈ 14 grams of water (the answer is given to two significant figures).
c. Since the hydrogen reacts with the oxygen in a 2:1 ratio, twice the number of moles of oxygen in hydrogen is consumed: 0.781 mol O2 × 2 = 1.562 mol H2. Since we began with 12.4 moles of H2, the remaining amount of excess H2 would be 12.4 - 1.562 = 10.838 mol H2. The mass of the excess hydrogen reactant would thus be (10.838 mol H2)(2 × 1.008 g/mol) ≈ 22 grams of hydrogen gas (the answer is given to two significant figures).
Answer:
When water temperature increases (right), the rate of evaporation also increases. In turn, the amount of water vapor in the "air space" above the water increases. ... But, with increased evaporation, more water molecules exist in the air above the water, which in turn increases the condensation rate.
