What is the element that is in period 5 and group 3?

Calculate the volume of oxygen required to burn 12.00 l of ethane gas, c2h6, to produce carbon dioxide and water, if the volumes

kirza4 [7]

The volume of oxygen required to burn 12.00 L ethane is calculated as follows

find the moles of C2H6 used

At STP 1 mole is always = 22.4 L, what about 12.00 L

= ( 12.00L x 1 moles) 22.4 L = 0.536 moles

write the reacting equation

2C2H6+ 7O2 = 4CO2 + 6H2O
by use of mole ratio between C2H6 :O2 which is 2:7 the moles of O2

= 0.536 x7/2= 1.876 moles

again at STP 1mole = 22.4 L what about 1.876 moles

= 22.4 L x 1.876 moles/ 1 mole = 42.02 L

8 0

3 years ago

Explain your reasoning. Match each explanation to the appropriate blanks in the sentences on the right.

skelet666 [1.2K]

Answer:

A (I_2(g), Br_2 (g), Cl_2 (g), F_2 (B): The ranking can best be explained by the trend entropy decreases as 5. molar mass decreases.

B (H_2O_2 (g), H_2S(g), H_2O(g): The ranking can best be explained by the decreases a trend entropy decreases as 3. molar mass and structure complexity decreases.

C. (C(s, amorphous), C(s, graphite), C(s, diamond): The ranking can best be explained by the trend entropy decreases as 4. structure complexity decreases.

Explanation:

Hello.

In this case, we can understand a higher entropy when more disorder is present and a lower entropy when less disorder is present, thus:

A (I_2(g), Br_2 (g), Cl_2 (g), F_2 (B): The ranking can best be explained by the trend entropy decreases as 5. molar mass decreases since iodine has the greatest molar mass (254 g/mol) and fluorine the least molar mass (38 g/mol).

B (H_2O_2 (g), H_2S(g), H_2O(g): The ranking can best be explained by the decreases a trend entropy decreases as 3. molar mass and structure complexity decreases since hydrogen peroxide weights 34 g/mol as well as hydrogen sulfide but the peroxide has more bonds (more complex, higher entropy).

C. (C(s, amorphous), C(s, graphite), C(s, diamond): The ranking can best be explained by the trend entropy decreases as 4. structure complexity decreases since diamond has a well-ordered structure and amorphous carbon has a very disordered one.

Best regards.

4 0

3 years ago

The chemical name of copper ii tetra sulphate pentahydrate

Anastasy [175]

hope it's helpful ❤❤❤

THANK YOU.

3 0

3 years ago

Which mixture is classified as a solution?

svlad2 [7]

Salt water is considered to be a solution

5 0

3 years ago

For the following reaction, the equilibrium constant Kc is 2.0 at a certain temperature. The reaction is endothermic. What do yo

jeyben [28]

Answer:

The correct answer is : 'the concatenation of NO will increase'.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in temperature occurs.

$2NOBr(g)\rightleftharpoons 2NO(g) + Br_2(g)$

As, this is an endothermic reaction, increasing temperature will add more heat to the system which move equilibrium in the forward reaction with decrease in temperature. Hence, the equilibrium will shift in the right direction.

So, the concatenation of NO will increase.

7 0

3 years ago