Question

A mother is 24 years older than her daughter.Before eight years she was seven times her daughter's age.Find their present ages​

Answer 1

Answer:

Mother's Present Age = 36 years

Daughter's Present Age = 12 years

Step-by-step explanation:

Let present age of mother be "m" and present age of daughter be "d"

Mother is 24 years older than her daughter, so we can write:

m = 24 + d

8 years ago, Mother was 7 times old as daughter, that would be:

m - 8 = 7(d - 8)

Note, since 8 years ago, both "m" and "d" have 8 subtracted from it.

Now we substitute Equation 1 into Equation 2 and solve for d:

$m - 8 = 7(d - 8)\\24+d - 8 = 7(d - 8)\\16+d=7d-56\\6d=72\\d=\frac{72}{6}\\d=12$

Mother age, m, would be:

m = 24 + d

m = 24 + 12

m = 36

Hence,

Mother's Present Age = 36 years

Daughter's Present Age = 12 years