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3 years ago

Predict the products of the decomposition of lithium nitride, Li3N

Chemistry

2 answers:

Veseljchak [2.6K]3 years ago

8 0

<h3><u>Answer;</u></h3>

D) Li + N2

<h3><u>Explanation;</u></h3>

A decomposition reaction is a type of chemical reaction in which one reactant yields two or more products.
<em><u>Lithium nitride undergoes thermal decomposition to produce Lithium and nitrogen gas. This reaction takes place at a temperature of 300° to 500°C in a vacuum.</u></em>
The equation for the reaction is;

2Li3N(s) → 6Li(s) + N2(g)

Lera25 [3.4K]3 years ago

7 0

Answer:

its D. i did it on usatestprep. Plz mark brainliest and thanks

Explanation:

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Is there a way to tell whether or not to put two double bonds or not. For example SeS2 seems to work if it has two double bonds

Nina [5.8K]

Your first step should be to analyse the compound. For example, if the compound is carbon, you know it always has a valence of four, so, if it has a formula C2H4 (ethylene) it obviously has a double bond. There are difficulties here because benzene C6H6 can be considered to have 6 1.5 C-C bonds, being aromatic.

A second step is to look at its structure. Double bonds are traditionally shorter than single bonds; triple bonds shorter still. Covalent bonds do have typical lengths, nevertheless you can still have problems.

<span>A third step is to consider reactivity. For example, if you have a C=C double bond, you can add, say, bromine to it Thus C2H4 gives C2H4Br2, and by adding two bromine atoms you know you have one double bond. Again, benzene becomes an awkward molecule, but because of this, you know benzene does not have double bonds in the traditional sense</span>

8 0

3 years ago

For the following reaction, 42.2 grams of potassium hydrogen sulfate are allowed to react with 21.4 grams of potassium hydroxide

ASHA 777 [7]

Answer:

53.99g

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

KHSO4(aq) + KOH(aq) —> K2SO4(aq) + H2O(l)

Step 2:

Determination of the masses of KHSO4 and KOH that reacted and the mass of K2SO4 produced from the balanced equation.

This is illustrated below:

Molar mass of KHSO4 = 39 + 1 + 32 + (16x4) = 136g/mol

Mass of KHSO4 from the balanced equation = 1 x 136 = 136g

Molar mass of KOH = 39 + 16 + 1 = 56g/mol

Mass of KOH from the balanced equation = 1 x 56 = 56g

Molar mass of K2SO4 = (39x2) + 32 + (16x4) = 174g/mol

Mass of K2SO4 from the balanced equation = 1 x 174 = 174g.

From the balanced equation above, 136g of KHSO4 reacted with 56g of KOH to produce 174g of K2SO4

Step 3:

Determination of the limiting reactant. This is illustrated below:

From the balanced equation above, 136g of KHSO4 reacted with 56g of KOH.

Therefore, 42.2g of KHSO4 will react with = (42.2 x 56)/136 = 17.38g of KOH.

From the above calculations, we can see that only 17.38g out of 21.4g of KOH given was needed to react completely with 42.2g of KHSO4.

Therefore, KHSO4 is the limiting reactant and KOH is the excess reactant.

Step 4:

Determination of the maximum mass of K2SO4 produced from the reaction.

In this case, the limiting reactant will be used as all of it is used up in the reaction. The limiting reactant is KHSO4 and the maximum amount of K2SO4 produced can be obtained as follow:

From the balanced equation above, 136g of KHSO4 reacted to produce 174g of K2SO4.

Therefore, 42.2g of KHSO4 will react to produce = (42.2 x 174)/136 = 53.99g of K2SO4.

Therefore, the maximum amount of K2SO4 produced is 53.99g.

8 0

3 years ago

Type the correct answer in each box.

Musya8 [376]

Answer:

1 . 26

2. 55.854

Explanation:

because atomic number is the number of proton in other words smaller number and the mass number is the number of neutrons and electrons in other words bigger number .

hope this make sense :)

6 0

3 years ago

What is the positive ion of calcium and nitrogen

Sergio [31]

Calcium, which is in Period 2 and has 2 valence electrons, has an ion of Ca 2+

This is because it can give up the two electrons to get a full outer shell.

Nitrogen, on the other hand, has 5 valence electrons. To get a full outer shell, it can either gain 3 electrons or lose 5. Since it is easier to gain 3, Nitrogen usually gains 3 electrons to form a N3- ion.

Even though it is rare, it is possible for Nitrogen to form a positive ion, which is N5+

Hope I helped!! xx

3 0

4 years ago

Calculate the frequency of the light emitted by ahydrogen atom

lesya [120]

Answer: $0.31\times 10^{16}Hz$ .

Explanation:

$E=\frac{hc}{\lambda}$

$\lambda$ = Wavelength of radiation

E= energy

Using Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2$

Where,

$\lambda$ = Wavelength of radiation = ?

$R_H$ = Rydberg's Constant

$n_f$ = Higher energy level = 4

$n_i$ = Lower energy level = 1

Z= atomic number = 1 (for hydrogen)

Putting the values, in above equation, we get

$\frac{1}{\lambda}=10973731.6m^{-1}\left(\frac{1}{1^2}-\frac{1}{4^2} \right )\times 1$

$\lambda=9.7\times 10^{-8}m$

The relationship between wavelength and frequency of the wave follows the equation:

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of the wave = ?

c = speed of light = $3\times 10^8ms^{-1}$

$\lambda$ = wavelength of the wave = $9.7\times 10^{-8}m$

$\nu=\frac{3\times 10^8ms^{-1}}{9.7\times 10^{-8}m}$

$\nu=0.31\times 10^{16}s^{-1}=0.31\times 10^{16}Hz$

The frequency of the light emitted by a hydrogen atom during a transition of its electron from the n = 4 to the n = 1 principal energy level is $0.31\times 10^{16}Hz$ .

5 0

3 years ago