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zysi [14]
3 years ago
8

The balanced equation for the reaction between iron sulfied and water is best represented by?​

Chemistry
1 answer:
nika2105 [10]3 years ago
4 0

FeS  +   H₂O    →    FeO   +    H₂S

Explanation:

  Iron Sulfide = FeS

  Water = H₂O

                FeS  +   H₂O    →    FeO   +    H₂S

To balance this equation, we can use a mathematical method. This involves solving simple algebraic equations

                 aFeS  +   bH₂O    →    cFeO   +    dH₂S

 a,b,c and d are the coefficients needed to balance up the equation:

      Conserving Fe: a = c

                           S:  a = d

                           H:  2b = 2d

                           O:  b = c

let a = 1, c= 1, b = 1 d = 1

     The balanced equation is:  FeS  +   H₂O    →    FeO   +    H₂S

learn more:

Balanced equation brainly.com/question/2612756

#learnwithBrainly

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The 1H-NMR of a compound with molecular formula C6H12O2 consists of four signals: 1.1 (triplet, integrating to 3 Hydrogens), 1.2
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Answer:

Isopropyl propionate  

Explanation:

1. Information from formula

The formula is C₆H₁₂O₂. A six-carbon alkane would have the formula C₆H₁₄. The deficiency of two H atoms indicates the presence of either a ring or a double bond.

2. Information from the spectrum

(a) Triplet-quartet

A 3H triplet and a 2H quartet is the classic pattern for a CH₃CH₂- (ethyl) group

(b) Septet-doublet

A 1H septet and a 6H doublet is the classic pattern for a -CH(CH₃)₂ (isopropyl) group

(c) The rest of the molecule

The ethyl and isopropyl groups together add up to C₇H₁₂.

The rest of the molecule must have the formula CO₂ and one unit of unsaturation. That must be a C=O group.

The compound is either

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(d) Well, which is it?

The O atom of the ester function should have the greatest effect on the H atom on the adjacent carbon atom.

The CH of an isopropyl is normally at 1.7. The adjacent O atom should pull it down perhaps 3.2 units to 4.9.  

The CH₂ of an ethyl group is normally at 1.2. The adjacent O atom should pull it down to about 4.4.

We see a signal at 5.0 but none near 4.4. The compound is isopropyl propionate.

3. Summary

My peak assignments are shown in the diagram below.

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