Answer:
1. Chromium
2. Chlorine.
3. Chlorine.
4. Chromium.
5. 12 electrons.
Explanation:
Hello,
In this case, the given reaction with the appropriate oxidation states turns out:
In such a way, the oxidation half-reaction is written for chromium as the reducing agent so it is oxidized from +3 to +6, nonetheless, since there are two chromiums undergoing such change, 6 electrons are being transferred as shown below:
On the other hand, chlorine's reduction half-reaction as the oxidizing agent result from the transfer of 6 electrons as well from +1 to 0, nonetheless, there are 6 chlorines undergoing such change:
Therefore, there are 12 electrons that are being transferred, 6 for chromium and 6 for chlorine.
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I think it is b because they travel per minute
Explanation:
(a) Molar mass of is 691.92 g/mol. And, there is 0.76 g of sodium monofluorophosphate () in 100 ml.
Molar mass of fluorine is 19 g/mol.
This means that in 691.92 g/mol there are 19 g/mol of fluorine is present. Hence, mass of fluorine present in 0.76 g is calculated as follows.
Mass of fluorine =
= 0.021 g
As, 1 g = 1000 mg. Hence, 0.021 g = 21 mg.
Therefore, mass of florine atoms in present was 21 mg.
(b) As we know that number of moles equal mass divided by molar mass.
Therefore, No. of moles of fluorine =
=
= 0.001 mol
Hence, according to mole concept in one mole there are atoms.
So, in 0.001 mole number of fluorine atoms will be calculated as follows.
atoms.
= atoms
Therefore, there are atoms of fluorine were present.
Answer:
The device can collect up to 1.5 kg (3.3 lbs) of waste per day and holds a total of 20 kg (44 lbs) of waste. To illustrate this more vividly: A Seabin can collect up to 90’000 plastic bags, 37’500 coffee cups or 16’500 PET bottles per year.
Explanation:
Not sure what you mean??
Answer:
2–Ethyl–3–methlypentanal.
Explanation:
To name the compound given in the question above, we must observe the following:
1. The functional group of the compound is Alkanal i.e Aldehyde,
—CHO and it is located at carbon 1.
Note: the aldehyde functional group is always at carbon 1 and there will be no need to state it's position in the compound.
2. The longest continuous carbon chain is 5 i.e pentane. But the presence of the functional group will replace the –e at the end of pentane with –al, making the name to the pentanal.
3. The substituents attached are:
a. Ethyl, CH2CH3 at carbon 2.
b. Methyl, CH3 at carbon 3.
4. Combine the above to get the name of the compound.
Therefore, the name of the compound is:
2–Ethyl–3–methlypentanal.