Answer : The volume of propane required are, 23.29 L
Solution : Given,
Mass of water = 75 g
Molar mass of water = 18 g/mole
First we have to calculate the moles of water.
Now we have to calculate the moles of propane.
The balanced chemical reaction will be,
From the reaction, we conclude that
As, 4 moles of water produces from 1 mole of propane
So, 4.16 moles of water produces from mole of propane
Now we have to calculate the volume of propane.
As, 1 mole of propane contains 22.4 L volume of propane gas
So, 1.04 mole of propane contains volume of propane gas
Therefore, the volume of propane required are, 23.29 L