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ANSWER
EXPLANATION
Coterminal angles are angles in standard position that have the same terminal side.
To find an angle in standard position that is coterminal with
We add or subtract multiples of
The first addition gives,
We add the second multiple to get,
Since this is the maximum value among the options, we end the addition here.
Let us now subtract the first multiple to get,
We end the subtraction here because this is the least value among the options.
Therefore the angles that are coterminal with
are
EXPLANATION
Coterminal angles are angles in standard position that have the same terminal side.
To find an angle in standard position that is coterminal with
We add or subtract multiples of
The first addition gives,
We add the second multiple to get,
Since this is the maximum value among the options, we end the addition here.
Let us now subtract the first multiple to get,
We end the subtraction here because this is the least value among the options.
Therefore the angles that are coterminal with
are
Hey there Fish Girl!
So, if![\left[\begin{array}{ccc}1/4 \end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F4%20%5Cend%7Barray%7D%5Cright%5D%20%20%20)
equals 50 miles, then we would do this multiplied by . . . .
So, if we would want to go to 3 whole, we would then have to go to the number 3 of course. So then, we do![\left[\begin{array}{ccc}4*3=12\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%2A3%3D12%5Cend%7Barray%7D%5Cright%5D%20%20%20)
and then from this, we would have to multiply this my 50.
The reason to why we would have to do this is because 1/4 of a mile is 50, so then, sense we are trying to get to the number 3, then, from doing this,we would determine a figure out how many miles this would conclude to be.
![\left[\begin{array}{ccc}12*50\end{array}\right] =\left[\begin{array}{ccc}\boxed{\boxed{600}} \ so \ far!\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2A50%5Cend%7Barray%7D%5Cright%5D%20%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B600%7D%7D%20%5C%20so%20%5C%20far%21%5Cend%7Barray%7D%5Cright%5D%20)
So, now, we have covered 3 as a whole, then we would have to see how 3/8 and also 1/4 can relate to each other.
So, in this case,
So, most likely, it would stay the same as it is, 1/4 because this is almost half to.
SO ALL WE WOULD NEED TO DO NOW IS TO ADD . . . . .
![\left[\begin{array}{ccc}\left[\begin{array}{ccc}\boxed{\boxed{600+50 \ or \frac{1}{4}=650}} \end{array}\right]\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B600%2B50%20%5C%20or%20%20%5Cfrac%7B1%7D%7B4%7D%3D650%7D%7D%20%5Cend%7Barray%7D%5Cright%5D%5Cend%7Barray%7D%5Cright%5D%20%20%20)
YOUR CORRECT AND FINAL ANSWER TO THIS QUESTION WOULD BE. . . .
![\left[\begin{array}{ccc}650 \ miles\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%20%5C%20miles%5Cend%7Barray%7D%5Cright%5D%20%20%20)
Hope this helps you fish Girl! :)
So, if
So, if we would want to go to 3 whole, we would then have to go to the number 3 of course. So then, we do
The reason to why we would have to do this is because 1/4 of a mile is 50, so then, sense we are trying to get to the number 3, then, from doing this,we would determine a figure out how many miles this would conclude to be.
So, now, we have covered 3 as a whole, then we would have to see how 3/8 and also 1/4 can relate to each other.
So, in this case,
So, most likely, it would stay the same as it is, 1/4 because this is almost half to.
SO ALL WE WOULD NEED TO DO NOW IS TO ADD . . . . .
YOUR CORRECT AND FINAL ANSWER TO THIS QUESTION WOULD BE. . . .
Hope this helps you fish Girl! :)