F(x)= 2/(x+1) and g(x)= -x2-12 => f(-7)= ? , g(2.5)= ?, g(f(- 0.5))= ?
In the expression of the function f(x) we will replace instead of x the number in bracket (-7) => f(-7) = 2/(-7+1)= 2/-6 = - 1/3
In the expression of the function g(x) we will replace instead of x number in bracket (2.5) => g(2.5) = - (2.5)squared -12= - 6.25 -12= - 18.25
Expression f(g(x)) or g(f(x)) is multiplication (composition) of the reflecting of functions f and g. We will do this in the following way => g(f(x))= g(2/(x+1))= -(2/(x+1))2 - 12= -(4/(x+1)2) -12= -4-12(x+1)2/(x+1)2=> we will replace instead of x the number in bracket (-0.5) or (-1/2) => g(f(-1/2) = -4-12((-1/2)+1)2/ ((-1/2+ 1)2= -4-12(1/2)2/(1/2)2=-4-12*(1/4)/(1/4)= (-4-3)/(1/4)=-28
Eaisier way => f(-1/2)=2/((-1/2)+1)=2/(1/2)= 4 g(4) -(4)2-12 = -16-12= -28
Significant figures are the digits that carry meaning to its measurement. Significant figures includes all the numbers excluding all the leading zeros, trailing zeros. All non zero digits are significant. Zeros between the non zero digits are significant. In a decimal number, trailing zeros are significant.
Now, consider the given number 0.23350
Since, in a decimal number all the trailing zeros are significant.
So, in the number 0.23350 there are five significant figures 2,3,4,5 and 0.
Therefore, there are 5 significant figures in the given number.
I’m not sure what the answer is, just trying to get points.... but I hope you find your answer :)
Hi,
Irrational means not a whole number so b,c, and d are irrational. but to be more safe i would go for d.
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