Answer
given,
range of the projectile = 4.3 m
time of flight = T = 0.829 s


v = 5.19 m/s
vertical component of velocity of projectile
v_y = gt'



a) Launch angle


θ = 38°
b) initial speed of projectile


v = 6.59 m/s
c) maximum height reached by the projectile



Answer:
P V = N R T ideal gas equation
P2 / P1 = T2 / T1 where the other variables are constant
P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi
So, the angular frequency of the blades approximately <u>36.43π rad/s</u>.
<h3>Introduction</h3>
Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. <u>Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle)</u>. Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :

With the following condition :
= angular frequency (rad/s)
= change of angle value (rad)- t = interval of the time (s)
<h3>Problem Solving</h3>
We know that :
= change of angle value = 1,000 revolution = 1,000 × 2π rad = 2,000π rad/s >> Remember 1 rev = 2π rad/s.- t = interval of the time = 54.9 s.
What was asked :
= angular frequency = ... rad/s
Step by step :



<h3>Conclusion :</h3>
So, the angular frequency of the blades approximately 36.43π rad/s.
If you have (1 x 10⁹) cubic meters of volume, and 1/2 gram of mass
in each cubic meter, then you have
(1/2 x 10⁹) grams = (5 x 10⁸) grams = (5 x 10⁵) kilograms of mass .
On Earth, that mass weighs 4,900,000 newtons .
(about 1,102,300 pounds)
(about 551 tons)
Explanation:
during the daytime the land gets hot and the hot air blows up to the sky and to feel the space the cool you are from the Sea blows to the land this phenomenon is called sea breeze similarly at night the hot air of sea goes up n cool air from land blows to sea which is called land breexe
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