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nadezda [96]
3 years ago
9

Kevin goes bowling. Whenever he bowls the ball, he transfers energy from his hand to the bowling ball. The amount of energy befo

re the transfer is ____________ the amount of energy after the transfer.
A. Less than
B. More than
C. Equal to
D. Not related to
Physics
1 answer:
g100num [7]3 years ago
3 0

Answer:the answer is C

Explanation:

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Wavelenght is 4.53x10^-7m

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Before a star is born, the matter that will become the star exists as a
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A long thin rod of mass M and length L is situated along the y axis with one end at the origin. A small spherical mass m1 is pla
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Answer:

= - 5.65\times 10^{-2} J

Explanation:

Given data:

L =2.00 *10^4 m

d = 18*10^4 m

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Gravitational energy is given as

U =- G \frac{m_1 m_2}{r}

mass per unit length is given as

\sigma = \frac{M}{L} = \frac{18 \times 10^6}{2\times 10^4 m} = 900 kg/m

calculating potential energy

dU ==-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *dm}{r}

=-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *\sigma dr}{r}

=-G*m_1*\sigma\int_{16\times 10^4}^{18\times 10^4} \frac{dr}{r}

=-G*m_1*\sigma \left | ln r \right |_{16\times 10^4}^{18\times 10^4}

=-G*m_1*\sigma ln(1.125)

=-6.673 \times 10^{-11}*8*10^6*900*ln(1.125)

= - 5.65\times 10^{-2} J

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2 years ago
Which part is not necessary to complete a circuit
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3 years ago
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Express the length of a marathon run of<br> 26 mi 385 yd in meters.<br> Answer in units of m.
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Answer:

1 mi = 5280 ft  * 12 in/ft = 63360 in

A convenient conversion factor (to remember) is 1 m = 39.37 in

63360 in / (39.37 in / m) = 1609.3 m

26 mi + 285 m = 26 * 1609.3 + 385 = 42,228 m

6 0
2 years ago
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