So basically, the first question after the word problem is asking you to write an equation to represent the value of Mama's car after a certain amount of years (t). Since the value of her car decreases by 3% each year, you could multiply 3% by the original value of her car, to find what 3% is, OR you could subtract 19,400 (the value of her car after 1 year) from 20,000 INSTEAD of multiplying 20,000 by 3%.
Equation: value=20,000 - 600t
To answer the next question, just plug it into the equation you created.
500<20,000 - 600t
-19500< -600t
32.5>t
Final Answer: It would take at least 32 and 1/2 years for the value of Mama's car to be less than $500.
Hope this helps!! :)
320 is on the Fourth quadrant:)
Answer:
36 will be the measure.
Hope it helps!!!
Step-by-step explanation:
Answer:
The WIP limit is 0.50 days.
Step-by-step explanation:
The Computation of WIP limits:
to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:
Value Added Time = 12 days (arriving time)
Non-Value-Added Time = 12 days (departure time)
Efficiency = Value Added / (Value Added + Non-Value Added)
= 12 / (12+12)
= 12 / 24
= 0.50 or 50%
the most obligatory throughput time will be 0.25 days to realize the profits
WIP limit = Throughput time / Efficiency
= 0.25 / 50%
= 0.50 days.
The WIP limit is 0.50 days.
Let's simplify step-by-step.
23
p
+
43
p
−
13
p
=
23
p
+
43
p
+
−
13
p
Combine Like Terms:
=
23
p
+
43
p
+
−
13
p
=
(
23
p
+
43
p
+
−
13
p
)
=
53
p
Answer:
