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Julli [10]
3 years ago
8

consider the numbers 3/10 and 4/13 compare the numbers find a rational number between the two given numbers

Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0
To find a number in between you could multiply 39/130 by 2/2 and 40/130 by 2/2 to get 78/260 and 80/260
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given a set of numbers n= {1,3,4,5,7}. if event a is the drawing of a number less than 4 and event b is the drawing of an even n
MAVERICK [17]
A OR b means that you add the individual probabilities...

P(<4)=2/5 and P(even)=1/5 so

P(<4 or even)=3/5
4 0
4 years ago
I have 100 points<br> i need some help!!
Anastaziya [24]
The possible answers might be 3 (or) -25. There’s no -25 among answers so I suppose it’s B.
6 0
3 years ago
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PLEASE EXPLAIN HOW TO DO THIS!!!
jeka94
2*100*64=? Just use a calculator to find the answer
8 0
4 years ago
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Determine which set of numbers can be the lengths of the sides of a triangle.
prisoha [69]

Answer:

A) 13, 10, 16

Step-by-step explanation:

The Triangle Inequality Theorem will help you solve this question. The Triangle Inequality Theorem states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side.

The options that are given are:

  • A) 13, 10, 16
  • B) 1, 2, 3
  • C) 5.2, 11, 4.9
  • D) 208, 9, 219

Lets solve each one to figure out if they could be the lengths of a triangle.

A) 13, 10, 16.

We can write three inequalities to see if the lengths are true.

13 + 10 > 16

10 + 16 > 13

13+ 16 > 10

Solve each one.

23 > 16

26 > 13

29 > 10

According to the information above, the set of numbers from option A does  fit the Triangle Inequality Theorem. Therefore, they are possible lengths.

B) 1, 2, 3

Write three inequalities:

1 + 2 > 3

2 + 3 > 1

3+ 1 > 2

Solve each.

3 > 3

5 > 1

4 > 2

As you see, only two lengths fit the theorem, but the third side (3 > 3) does not. This set of lengths is not a possible set for a triangle.

C) 5.2, 11, 4.9

Write three inequalities:

5.2 + 11  > 4.9

4.9 + 11 > 5.2

5.2 + 4.9 > 11

Solve each.

16.2 > 4.9

15.9 > 5.2

10.1 > 11

As you see, only two sides lengths can repsent the lengths of a triangle but the third does not, so its not a possible set of lengths for a triangle.

D) 208, 9, 219

Write three inequalities:

208 + 9 > 219

219 + 9 > 208

208+ 219 > 9

Solve each.

217 > 219

228 > 208

427 > 9

Although two lengths fit the theorem, one length does not, so this a not a possible set of lengths.

In summary, only one set of lengths is possible for a triangle, with is A.

4 0
3 years ago
Find two fractions with a product between 10 and 11. SHOW YOUR WORK
Ray Of Light [21]
2/1 * 5/1 = 10
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3 years ago
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