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d1i1m1o1n [39]
4 years ago
14

A circle with area 36pi has a sector with a central angle of 48°. what is the area of the sector?

Mathematics
1 answer:
Elza [17]4 years ago
4 0

Answer:4.8π

Step-by-step explanation:

Φ=48°

Area of circle=36π

Area of circle=π x r^2

36π=πr^2

Dividing both sides by π we get

r^2=36π/π

r^2=36

Take them square root of both sides

√(r^2)=√(36)

r=6

Area of sector=Φ/360 x π x r x r

Area of sector=48/360 x π x 6 x 6

Area of sector=(48xπx6x6)/360

Area of sector=1728π/360

Area of sector=4.8π

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Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)
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we know that

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if a -------> the parabola open downward (vertex is a maximun)

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convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

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The function f(x)=(x+1)(x-2) does not have a vertex on the y-axis

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f(x)=(x-2)(x+2)

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