Question

A circle with area 36pi has a sector with a central angle of 48°. what is the area of the sector?

Answer 1

Answer:4.8π

Step-by-step explanation:

Φ=48°

Area of circle=36π

Area of circle=π x r^2

36π=πr^2

Dividing both sides by π we get

r^2=36π/π

r^2=36

Take them square root of both sides

√(r^2)=√(36)

r=6

Area of sector=Φ/360 x π x r x r

Area of sector=48/360 x π x 6 x 6

Area of sector=(48xπx6x6)/360

Area of sector=1728π/360

Area of sector=4.8π