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Mama L [17]
3 years ago
15

How can a sample of uranium-235 that has critical mass be induced to react? it must be spilt with a laser. it must be fused to a

helium nucleus. it must be bombarded with neutrons. it must be shot with light speed electrons?
Chemistry
2 answers:
Triss [41]3 years ago
8 0
It needs to undergo the process of fission which requires it to be bombarded with fast moving neutrons so your answer would be C.it must be bombarded with neutrons
weeeeeb [17]3 years ago
5 0
It must be bombarded with neutrons
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How many moles are in 2.6 x 10 ^25 atoms of Li?​
Cerrena [4.2K]

Answer:

43 mole

Explanation:

Given data:

Number of atoms of Li = 2.6× 10²⁵ atoms

Number of moles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.6× 10²⁵ atoms × 1 mole / 6.022 × 10²³ atoms

0.43 × 10² mole

43 mole

5 0
3 years ago
A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128
alisha [4.7K]

Answer: The final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

Explanation:

The given data is as follows.

mass = 7.62 g,           T_{2} = 10.8^{o}C

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

       q = mC \times \Delta T    

          = 7.62 g \times 4.184 J/^{o}C \times (52.3 - T)

Now, heat gained by lead will be calculated as follows.

       q = mC \times \text{Temperature change of lead}  

           = 2.04 \times 0.128 \times (T - 11.0)

According to the given situation,

     Heat lost = Heat gained

7.62 g \times 4.184 J/^{o}C \times (52.3 - T) = 2.04 \times 0.128 \times (T - 11.0)

        T = 50.26^{o}C

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

7 0
3 years ago
Can someone please answer this for me
geniusboy [140]

Answer:

phone, microwave, internet box

5 0
2 years ago
For the reaction 2 nh3 + ch3oh → products, how much ch3oh is needed to react with 93.5 g of nh3? 1. 1.31 mol 2. 46.8 mol 3. 2.75
DENIUS [597]
3.2.75 mol is the answer.
6 0
3 years ago
Read 2 more answers
The density of glycerin is 1.26 g/cm^3. Which substance stink in glycerin?
Fiesta28 [93]

The answer to your question is aluminum.

6 0
2 years ago
Read 2 more answers
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