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3 years ago

Which atomic model proposed that electrons move in specific orbits around the nucleus of an atom?

Chemistry

2 answers:

Tatiana [17]3 years ago

8 0

Answer: The correct answer is Bohr's atomic model.

Explanation:

For the given options:

Dalton's atomic model: This model states that every matter is made up of smallest unit known as atom.

Thomson's atomic model: He proposed a model known as plum pudding model. He considered atom to be a pudding of positive charge in which negative particles are embedded such as plum.

Rutherford's atomic model: He gave an experiment known as gold foil experiment. In his model, he concluded that in an atom, there exist a small positive charge in the center.

Bohr's atomic model: This model states that electron revolve around the nucleus in discrete orbits in an atom.

Quantum atomic model: This model determines the location of electrons in an atom in a 3-D space.

Hence, the correct answer is Bohr's atomic model.

Brilliant_brown [7]3 years ago

4 0

Hi there ,
The Bohre's atomic model represents movement of electrons in specific orbit around the nucleus of an atom.
Hope it helps.

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9 How many grams of O₂ are needed to produce 15.5 g Fe₂O3 in the following reaction? Fe(s) + O₂(g) → Fe₂O3 (s)

Slav-nsk [51]

Answer:

Explanation:

so u can work out the amount of moles in FeO3 by doing mr of fe3o3 is 55.8*3+16*3=215.4

moles= mass/mr so you do 15.5g/215.4=0.0719 moles

then using 1 to 1 ratio so O2 moles is 0.0719

then use the equation mass=mole*mr

so 0.0719*16=1.15g

hope this make sense :)

8 0

3 years ago

Which intermolecular forces increase rapidly with increasing molecular size?

blondinia [14]

LONDON DISPERSION FORCES

8 0

3 years ago

3. How did organizing the periodic table by atomic number help scientists?

forsale [732]

Scientists developed symbols and gave the elements numbers to help organize the elements by their chemical properties. The periodic table helps identify the underlying chemical and physical traits of the elements.

4 0

3 years ago

How many milliliters of C5H8 can be made from 366 mL C5H12 ?

zlopas [31]

The number of Ml of C₅H₈ that can be made from 366 ml C₅H₁₂ is 314.7 ml of C₅H₈

calculation

step 1: write the equation for formation of C₅H₈

C₅H₁₂ → C₅H₈ + 2 H₂

Step 2: find the mass of C₅H₁₂

mass = density × volume

= 0.620 g/ml × 366 ml =226.92 g

Step 3: find moles Of C₅H₁₂

moles = mass÷ molar mass

from periodic table the molar mass of C₅H₁₂ = (12 x5) +( 1 x12) = 72 g/mol

moles = 226.92 g÷ 72 g/mol =3.152 moles

Step 4: use the mole ratio to determine the moles of C₅H₈

C₅H₁₂:C₅H₈ is 1:1 from equation above

Therefore the moles of C₅H₈ is also = 3.152 moles

Step 5: find the mass of C₅H₈

mass = moles x molar mass

from periodic table the molar mass of C₅H₈ = (12 x5) +( 1 x8) = 68 g/mol

= 3.152 moles x 68 g/mol = 214.34 g

Step 6: find Ml of C₅H₈

=mass / density

= 214.34 g/0.681 g/ml = 314.7 ml

8 0

3 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

Answer: The mass of original oxalic acid sample is 6.75 grams

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

2 years ago