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Dafna1 [17]
3 years ago
8

Which atomic model proposed that electrons move in specific orbits around the nucleus of an atom?

Chemistry
2 answers:
Tatiana [17]3 years ago
8 0

<u>Answer:</u> The correct answer is Bohr's atomic model.

<u>Explanation:</u>

For the given options:

<u>Dalton's atomic model:</u> This model states that every matter is made up of smallest unit known as atom.

<u>Thomson's atomic model:</u> He proposed a model known as plum pudding model. He considered atom to be a pudding of positive charge in which negative particles are embedded such as plum.

<u>Rutherford's atomic model:</u> He gave an experiment known as gold foil experiment. In his model, he concluded that in an atom, there exist a small positive charge in the center.

<u>Bohr's atomic model:</u> This model states that electron revolve around the nucleus in discrete orbits in an atom.

<u>Quantum atomic model:</u> This model determines the location of electrons in an atom in a 3-D space.

Hence, the correct answer is Bohr's atomic model.

Brilliant_brown [7]3 years ago
4 0
Hi there ,
The Bohre's atomic model represents movement of electrons in specific orbit around the nucleus of an atom.
Hope it helps.
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         Width of Styrofoam = 24.0 cm

          Length of Styrofoam = 36.0 cm

          Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

                  Volume = length × width × height

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                                 = 4320 cm^{3}

or,                             = 4.32 \times 10^{3} cm^{3}

As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.

So, volume of water displaced is as follows.

          24.0 cm × 36.0 cm × 2.0 cm

         = 1.73 \times 10^{3} cm^{3}

Hence, mass of displaced water is as follows.

                 mass = density × volume

                           = 1.00 g/cm^{3} \times 1.73 \times 10^{3} cm^{3}

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Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.

             Mass of water displaced = mass of book + mass of Styrofoam

                  1.73 \times 10^{3} g = 1500 g + mass of Styrofoam

                   (1730 - 1500) g = mass of Styrofoam

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Therefore, calculate the density of Styrofoam as follows.

                   Density = \frac{mass}{volume}  

                                 = \frac{230}{4.32 \times 10^{3} cm^{3}}

                                 = 53.24 \times 10^{-3} g cm^{-3}

Thus, we can conclude that the density of Styrofoam is 53.24 \times 10^{-3} g cm^{-3}.

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