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3 years ago

Which atomic model proposed that electrons move in specific orbits around the nucleus of an atom?

Chemistry

2 answers:

Tatiana [17]3 years ago

8 0

Answer: The correct answer is Bohr's atomic model.

Explanation:

For the given options:

Dalton's atomic model: This model states that every matter is made up of smallest unit known as atom.

Thomson's atomic model: He proposed a model known as plum pudding model. He considered atom to be a pudding of positive charge in which negative particles are embedded such as plum.

Rutherford's atomic model: He gave an experiment known as gold foil experiment. In his model, he concluded that in an atom, there exist a small positive charge in the center.

Bohr's atomic model: This model states that electron revolve around the nucleus in discrete orbits in an atom.

Quantum atomic model: This model determines the location of electrons in an atom in a 3-D space.

Hence, the correct answer is Bohr's atomic model.

Brilliant_brown [7]3 years ago

4 0

Hi there ,
The Bohre's atomic model represents movement of electrons in specific orbit around the nucleus of an atom.
Hope it helps.

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When Earth is between the Moon and the Sun, how is the Moon seen?

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It is B, because it is an eclipse.

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Where does the energy water uses to create ice go?

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Answer:

he free energy goes down as the water freezes. Here are the important terms: The energy of the interactions between the water molecules goes down as they line up in the stable ice positions. This lost energy flows out into the environment as heat, increasing the entropy of

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3 years ago

10) Nitrogen and hydrogen react together to form ammonia.

alexandr402 [8]

Answer:

<h2>C 28 tonnes</h2>

Explanation

7 tonnes-8.5 ammonia

1 ton will be 8.5/7=1.21

we now know what 1 ton of nitrogen is equal to

so now,34/28 that is equal to 1.21

1.21=1.21

So the answer would be C. 28 tonnes

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Answered by: FieryAnswererGT

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2 years ago

Given 4.80g of ammonium carbonate, find:

V125BC [204]

Answer:

1) 0.05 mol.

2) 0.1 mol.

3) 0.05 mol.

4) 0.4 mol.

5) 2.4 x 10²³ molecules.

Explanation:

1) Number of moles of the compound:

no. of moles of ammonium carbonate = mass/molar mass = (4.80 g)/(96.09 g/mol) = 0.05 mol.

2) Number of moles of ammonium ions :

Ammonium carbonate is dissociated according to the balanced equation:

(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.

It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.

∴ The no. of moles of NH₄⁺ ions in 0.05 mol of (NH₄)₂CO₃ = (2.0)(0.05 mol) = 0.1 mol.

3) Number of moles of carbonate ions :

Ammonium carbonate is dissociated according to the balanced equation:

(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.

It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.

∴ The no. of moles of CO₃²⁻ ions in 0.05 mol of (NH₄)₂CO₃ = (1.0)(0.05 mol) = 0.05 mol.

4) Number of moles of hydrogen atoms:

Every 1.0 mol of (NH₄)₂CO₃ contains:

2.0 moles of N atoms, 8.0 moles of H atoms, 1.0 mole of C atoms, and 3.0 moles of O atoms.

∴ The no. of moles of H atoms in 0.05 mol of (NH₄)₂CO₃ = (8.0)(0.05 mol) = 0.4 mol.

5) Number of hydrogen atoms:

It is known that every mole of a molecule or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.

Using cross multiplication:

1.0 mole of H atoms contains → 6.022 x 10²³ atoms.

0.4 mole of H atoms contains → ??? atoms.

∴ The no. of atoms in 0.4 mol of H atoms = (6.022 x 10²³ molecules)(0.4 mole)/(1.0 mole) = 2.4 x 10²³ molecules.

8 0

3 years ago

When 45 g of an alloy, at 25°C, are dropped into 100.0g of water, the alloy absorbs 956J of heat. If the temperature of the allo

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You can use this formula to help:

$c = \frac{q}{m \: \times \: change \: in \: t}$

Where:

C = specific heat

q = heat

m = mass

t = temperature

What we know:

C = unknown

q = 956 J

m = 45 g

change in t = 12°C because 37°C - 25°C = 12°C

Plug known values into the formula:

C = 956 J / (45 g) (12°C) and we are left with a specific heat of 1.77J/g°C

Now, convert Joules to calories and then you get:

Answer: A. 0.423 cal/g°C

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