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SIZIF [17.4K]
3 years ago
12

The picture below is a great example of __________ biodiversity.

Chemistry
1 answer:
ss7ja [257]3 years ago
6 0
Low because it is not diverse. It is just seed corn.
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What would you need to do to calculate the molality of 0.2 kg of NaCl in 3 kg
enot [183]

Answer:

D. Convert the 0.2 kg of NaCl to moles of NaCl

Explanation:

The molality equation looks like this:

Molality = moles of solute / mass (kg) of solvent

In this case, the solute is NaCl and the solution is water. So, if you have been given NaCl in kg, you need to convert it to grams and then to moles in order to plug it into the equation.

6 0
2 years ago
What is the definition of an Arrhenius acid?
Lorico [155]

Answer:

I <u>think</u> your answer is: C. ("An Arrhenius acid increases [H +] in the solution.")

Explanation:

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions (H + ); that is, an acid increases the concentration of H + ions in an aqueous solution. This causes the protonation of water, or the creation of the hydronium (H 3 O +) ion.

Hopefully this helps!

Have a great day! ^^

5 0
3 years ago
HELP ASAP<br> In which reaction are the atoms of elements rearranged?
hammer [34]

Answer:

C. Explain ONE way in which the USA & USSR competed against each other during the Cold

War in the Post-World War Two period (c. 1945-present)

HURRY

Dr. Khan works for the marketing department of a company that manufactures mechanical toy dogs. Dr. Khan has been asked to assess the effectiveness of a new advertising campaign that is designed to be most persuasive to people with a certain personality profile. She brought four groups of participants to the lab to watch the video advertisements and to measure the likelihood that they would purchase the toy, both before and after watching the ad. The results of Dr. Khan’s study are presented below.

Part A

Explain how each of the following concepts applies to Dr. Khan’s research.

Survey

Dependent variable

Big Five theory of personality

Part B

Explain the limitations of Dr. Khan’s study based on the research method used.

Explain what Dr. Khan’s research hypothesis most likely was.

Part C

Use the graph to answer the following questions.

How did the trait of agreeableness affect how people responded to the new ad campaign?

How did the trait of conscientiousness affect how people responded to the new ad campaign?

5 0
3 years ago
Read 2 more answers
How to solve for K when given your anode and cathode equations and voltage
Aleks04 [339]

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

3 0
3 years ago
A three-step process for producing molten iron metal from Fe2O3 is: 3Fe2O3 + CO → 2Fe3O4 + CO2 Fe3O4 + CO → 3FeO + CO2 FeO + CO
miskamm [114]

Answer:

There is 100.4652 kg of iron produced from 390 kg of Fe2O3

Explanation:

<u>Step 1</u>: Given data

3Fe2O3 + CO → 2Fe3O4 + CO2

Fe3O4 + CO → 3FeO + CO2

FeO + CO → Fe + CO2

Mass of Fe2O3 = 390 kg = 390000 grams

Molar mass of Fe2O3 = 159.69 g/moles

<u>Step 2: </u>Calculate moles of Fe2O3

Moles of Fe2O3 = mass of Fe2O3 / Molar mass of Fe2O3

Moles of Fe2O3 = 390000 grams / 159.69 g/moles = 2442.2 moles

<u>Step 3</u>: Calculate expected moles of Fe3O4

In the first equation, for 3 moles of Fe2O3 consumed ,we get 2 moles of Fe3O4. The mole ratio is 3:2

This means if we consume 2442.2 moles of Fe2O3, there will be produced 2/3 * 2442.2 = 1628.2 moles of Fe3O4

Since the yield for the step is only 84.6 %

This will be 0.846 * 1628.2 = 1377.4 moles of Fe3O4

<u>Step 4:</u> Calculate expected moles of FeO

In the second equation, for 1 mole of Fe3O4 consumed, there is produced 3 moles of FeO

This means for 1377.4 moles of Fe3O4 consumed, there is 3*1377.4 = 4132.2 moles of FeO produced

Since the yield for the step is only 50.8%

This will be 0.508 * 4132.2 = 2099.2 moles of FeO

<u>Step 5:</u> Calculate expected moles of Fe

In the third equation, for 1 mole of FeO consumed, there is produced 1 mole of Fe.

This means for 2099.2 moles of FeO consumed, there is also 2099.2 moles of Fe produced

Since the yield is only 85.7%

This will be 0.857 * 2099.2 = 1799 moles of Fe

<u>Step 6:</u> Calculate mass of Fe

Mass of Fe = moles of Fe * Molar mass of Fe

Mass of Fe = 1799 moles of Fe * 55.845 g/moles = 100465.2 grams = 100.4652 kg of Fe

There is 100.4652 kg of iron produced from 390 kg of Fe2O3

6 0
4 years ago
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