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ryzh [129]
3 years ago
5

Please help I'm really bad at logorithms.

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0
Sorry to hear that you already took the test. Here is how to do the problem:

2ˣ = 128               
Let's take log base 10 of both sides.
For simplicity, we'll just use the symbol log to mean log₁₀

log (2ˣ) = log (128)                   Remember that log(yˣ) = x log(y)
x log (2) = log (128)                 Divide both sides by log(2) to get x by itself
x = log (128) ÷ log (2)
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