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Marizza181 [45]
3 years ago
10

Can someone please help me?Am I correct? Please let me know ASAP. I will give a brainlest:)

Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer:

My neck my back my and my

Step-by-step explanation:

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I need help! I'm *so* confused! I will mark Brainliest
Naddik [55]

Answer:

(-2,21)

Step-by-step explanation:

2 days ago, Paulo's commute time was halfway between his commute times 8 and 9 days ago.

8 days ago means that x-coordinate -8 represents this day. Count 8 units to the left and find that when x = -8, y = 24 minutes.

9 days ago means that x-coordinate -9 represents this day. Count 9 units to the left and find that when x = -9, y = 18 minutes.

Find halfway commute time between points (-8,24) and (-9,18):

y=\dfrac{24+18}{2}=\dfrac{42}{2}=21,

then coordinates that Paulo should graph are

(-2, 21)

(-2 means 2 days ago, 21 is the halfway)

5 0
3 years ago
I have no clue what the answer is.
Vera_Pavlovna [14]

Area of the word ME = 20 square units

Solution:

Picks' Theorem:

$Area=I+\frac{B}{2}-1$

where <em>I </em>is the interior points and <em>B</em> is the points on the boundary.

Let us first find the area of the letter M:

Number of interior points in M = 0

Number of points in the boundary = 22

Using pick's theorem,

Area of M = 0+\frac{22}{2}-1

Area of M = 10 square units

Now, find the area of the letter E:

Number of interior points in E = 0

Number of points in the boundary = 22

Using pick's theorem,

Area of E = 0+\frac{22}{2}-1

Area of E = 10 square units

Area of the word ME = Area of M + Area of E

                                   = 10 square units + 10 square units

Area of the word ME = 20 square units

7 0
4 years ago
When new, a standard tire has 10/32 inches of tread. When only 2/32 inches of tread remains, the tire needs to be replaced. If t
san4es73 [151]

Answer:

\frac{1}{160} \ inches

Step-by-step explanation:

The computation of the thickness of tire rubber for every lost 1,000 driven is shown below:

Data provided in the question

Inches of tread = \frac{10}{23}

In case of replaced = \frac{2}{3}

Based on the above information

Now in 40,000 miles, the ratio is

= \frac{10 - 2}{32} \\\\ = \frac{1}{4}

And for every 1,000 miles driven,  the thickness is

= \frac{1}{4 \times 40,000} \times 1,000 \\\\ = \frac{1}{160} \ inches

hence, the thickness of tire rubber is \frac{1}{160} \ inches

7 0
3 years ago
Look at the picture, it’s easy
Maurinko [17]

Answer:

(1,0.85)

Step-by-step explanation:

(x,y) = (t,d)

t = 1 minute

d = 0.85 feet

6 0
3 years ago
Read 2 more answers
Kevin has $1427 in a savings account. His brother, Harley has saved an amount with a 4 that is 1/10 the value of the 4 in Kevin'
Paul [167]
I'm guessing 400$????
3 0
3 years ago
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