<h3>
Answer:</h3>
49500 kgm/s
<h3>
Explanation:</h3>
Data given;
- First car; Mass = 1100 kg
- Velocity = 30 m/s
- Second car; mass = 1100 kg
- Velocity = 15 m/s
We are required to calculate the total momentum of the system.
- We need to know that momentum is calculated by multiplying the velocity of a body by its mass.
- Therefore;
Momentum of the first car = 1100 kg × 30 m/s
= 33,000 kgm/s
Momentum of the second car = 1100 kg × 15 m/s
= 16,500 kgm/s
Therefore;
Total momentum = 33,000 kgm/s + 16,500 kgm/s
= 49500 kgm/s
Thus, the total momentum of the system is 49500 kgm/s
Your question asks what the slope of a Position vs. Time graph represents.
Your answer would be Velocity.
The slope of a Position vs. Time graph would represent the velocity of the object.
If the slope is positive, then the object has a positive velocity ,in which it is going forward.
If the slope is negative, then the object has a negative velocity, which means that it's going the opposite direction, or backwards.
If the slope is at a "horizontal" position, this means that the object is stopped or isn't moving at all.
After three half-lives have elapsed, the amount of an 8.0 g sample of a radionuclide that remains undecayed is 1.0 g.
<h3>What is Half-Life?</h3>
Half-Life refers to the time it takes for half the amount of a substance to disappear or change.
The nucleus of the atoms of radioactive elements disintegrate to half their starting amounts after every Half-Life.
After three half-lives one-eight of the original atoms remain.
Therefore, after three half-lives have elapsed, the amount of an 8.0 g sample of a radionuclide that remains undecayed is 1.0 g.
Learn more about Half-Life at: brainly.com/question/26689704
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Answer:
34 m/s
Explanation:
The law of conservation of linear momentum dictates that the sum of initial and final momentum should be equal. Momentum is a product of mass and velocity.
Since the canon recoils, its recoil velocity is opposite hence
MV=nu where M and n are mass of cannon and cannoball respectively, v and u are the velocities of cannon and cannon balls respectively.
Substituting 200 kg for M and 1.7 m/s for v then 10 kg for n
200*1.7=10u
U=200*1.7/10=34 m/s
