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4 years ago

What does the slope of a Position vs. Time graph represent?

Physics

1 answer:

attashe74 [19]4 years ago

7 0

Your question asks what the slope of a Position vs. Time graph represents.

Your answer would be Velocity.

The slope of a Position vs. Time graph would represent the velocity of the object.

If the slope is positive, then the object has a positive velocity ,in which it is going forward.

If the slope is negative, then the object has a negative velocity, which means that it's going the opposite direction, or backwards.

If the slope is at a "horizontal" position, this means that the object is stopped or isn't moving at all.

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You are loading a toy dart gun, which has two settings, the more powerful with the spring compressed twice as far as the lower s

Amiraneli [1.4K]

Answer:

option A

Explanation:

given,

compression for lower setting = x

work done to compress in lower setting = 5 J

compression in higher setting, x' = 2 x

work done in higher setting = ?

Work done in compression of spring at lower setting

$W = \dfrac{1}{2}kx^2$

$5 = \dfrac{1}{2}kx^2$ ............(1)

Work done in compression of spring at higher setting

$W' = \dfrac{1}{2}kx'^2$

$W'= \dfrac{1}{2}k(2x)^2$

$W'= 4\times \dfrac{1}{2}kx^2$

$W'= 4\times W$

from equation (1)

$W'= 4\times 5$

W' = 20 J

Work take for the higher setting is equal to 20 J

Hence, the correct answer is option A

4 0

3 years ago

How does a tire of a car interact with the road

choli [55]

Answer:

friction

Explanation:

the road is the pathway for the vehicle so the tures create friction to stay sturdie

7 0

3 years ago

A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3

shusha [124]

Answer:

$x_2 = -2.3356$

$v = -1.384 \ m/s$

Explanation:

From the question we are told that

The initial position of the particle is $x_1 = 0.180 \ m$

The initial velocity of the particle is $u = 0.060 \ m/s$

The acceleration is $a = -0.380 \ m/s^2$

The time duration is $t = 3.80 \ s$

Generally from kinematic equation

$v = u + at$

=> $v = 0.060 + (-0.380 * 3.80)$

=> $v = -1.384 \ m/s$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here s is the distance covered by the particle, so

$(-1.384)^2 = (0.060)^2 + 2(-0.380)* s$

=> $s = -2.5156 \ m$

Generally the final position of the particle is

$x_2 = x_1 + s$

=> $x_2 = 0.180 + (-2.5156)$

=> $x_2 = -2.3356$

6 0

3 years ago

A physicist is constructing a solenoid. She has a roll of insulated copper wire and a power supply. She winds a single layer of

Leni [432]

Answer:

P =105.44 W

Explanation:

Given that

D= 10 cm ,L= 60 cm

d= 0.1 cm ,B= 6.4 mT

ρ= 1.7 x 10⁻⁸ Ω · m

The number of turns N

N= L/d

N= 60/0.1 = 600 turns

Length of wire

Lc= πDN

Lc= 3.14 x 0.1 x 600

Lc=188.4 m

The magnetic filed given as

$B=\dfrac{\mu_oNI}{L}$

$I=\dfrac{BL}{\mu_oN}$

Now by putting the values

$I=\dfrac{0.0064\times 0.6}{4\pi \times 10^{-7}\times 600}$

I=5.09 A

The resistance R given as

$R=\dfrac{\rho L_c}{A}$

$A=\dfrac{\pi}{4}\times d^2$

$A=\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2$

$R=\dfrac{1.7\times 10^{-8} \times 188.4}{\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2}$

R=4.07 Ω

Power P

p =I²R

P= 5.09² x 4.07 W

P =105.44 W

5 0

3 years ago

Can someone answer this.

klemol [59]

Take left to be the negative direction, and right to be positive. That means the forces on the squirrel would be -2N and 3N.

Add all the forces to find the net force on the squirrel. -2N+3N=1N

Because the positive direction is to the right, the net force of 1N is directed to the right.

4 0

4 years ago