All categories

4 years ago

What does the slope of a Position vs. Time graph represent?

Physics

1 answer:

attashe74 [19]4 years ago

7 0

Your question asks what the slope of a Position vs. Time graph represents.

Your answer would be Velocity.

The slope of a Position vs. Time graph would represent the velocity of the object.

If the slope is positive, then the object has a positive velocity ,in which it is going forward.

If the slope is negative, then the object has a negative velocity, which means that it's going the opposite direction, or backwards.

If the slope is at a "horizontal" position, this means that the object is stopped or isn't moving at all.

You might be interested in

To decrease the angle between the anterior surface of the foot and anterior surface of the lower leg is described as:

Westkost [7]

Answer:

dorsiflexion

Explanation:

To decrease the angle between the anterior surface of the foot and anterior surface of the lower leg is described as: dorsiflexion

7 0

3 years ago

Read 2 more answers

The emission of electrons from a metal caused by light striking metal

Mashutka [201]

I believe it is D, although you may should learn about all four of these laws.

5 0

4 years ago

Read 2 more answers

A solenoidal coil with 21 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 25.0 cm long

77julia77 [94]

A) We need to calculate the Magnetic flux of a Solenoid,

$\Phi = BA$

Where B is the magnetic field and A the Area.

$B=\frac{\mu_0 N_2 I}{l}$

Here \mu_0 is the permeability constant, I the current and N number of turns.

Replacing we have,

$\Phi = \frac{\mu_0 N_2 I}{l}(\pi r^2)$

$\Phi = \frac{(4\pi*10^{-7})(350)(0.12)}{25*10^{-2}} (\pi*\frac{2.5*10^{-2}}{2}^2)$

$\Phi = 1.036*10^{-7}Wb$

B) We calculate the mutual inductance, so

$M=\frac{N_1 \Phi}{i}$

$M=\frac{21*1.036*10^{-7}}{0.12}$

$M=1.813*10^{-5}H$

c) We calculate the emf

$\epsilon = -M \frac{dI}{dt}$

$\epsilon = -1.813*10^{-5}*1700$

$\epsilon= -0.030V$

3 0

3 years ago

A person throws a ball straight up into the air with a speed of 7.3m/s. How high does the ball go?

Colt1911 [192]

Answer:

2.6645m

Explanation:

applying motion equations we can find the answer,

$v^{2}=u^{2} +2as$

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

s = distance traveled

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g =10 m/s2 downwards)

that is,

$v^{2}=u^{2} +2as\\0=7.3^{2} -2*10*s\\s=2.6645m$

4 0

4 years ago

How do scientists use creativity in their careers?

vovikov84 [41]

Scientist judge each others work based mostly on how creative it is.

4 0

4 years ago

Read 2 more answers