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Ksju [112]
4 years ago
7

Old cannons were built on wheeled carts, both to facilitate moving the canon and to allow the canon to recoil when fired. When a

200 kg canon in car recoils at 1.7 m/s, at what velocity would a 10 kg cannonball leave the Cannon?
Physics
1 answer:
dolphi86 [110]4 years ago
6 0

Answer:

34 m/s

Explanation:

The law of conservation of linear momentum dictates that the sum of initial and final momentum should be equal. Momentum is a product of mass and velocity.

Since the canon recoils, its recoil velocity is opposite hence

MV=nu where M and n are mass of cannon and cannoball respectively, v and u are the velocities of cannon and cannon balls respectively.

Substituting 200 kg for M and 1.7 m/s for v then 10 kg for n

200*1.7=10u

U=200*1.7/10=34 m/s

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4 0
3 years ago
Please help me !!
avanturin [10]
The correct answer is B
5 0
3 years ago
Find the instantaneous acceleration at t=ls for an object moving along a straight axis with velocity function:
Maru [420]
The answer is A.
Explanation:
We know that the average acceleration a for an interval of time Δt is expressed as:

a = Δv
Δt
where Δv is the change in velocity that occurs during Δt.
e formula for the instantaneous acceleration a is almost the same, except that we need to indicate that we're interested in knowing what the ratio of Δv to Δt approaches as Δt approaches zero.

We can indicate that by using the limit notation.

So, the formula for the instantaneous acceleration is:

a = lim Δv
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8 0
3 years ago
Two trains are on separate but parallel tracks running east and west. One has a speed of 90 km/h, the other 80 km/h. Initially,
Tanzania [10]

Answer: 4 hours

Explanation: Their approach rate is 100+140 or 240 km/h and 960/240 which equals 4 hours

4 0
4 years ago
An equilateral triangle has a height of 3.32 cm. Draw the picture and use this information to determine the length of the sides
Westkost [7]

Answer:

The answer is  a=b=c=3.833 cm

Explanation:

Lets call the variables a=side a b=side b c=side c

We have that the formula of the equilateral triangle for its height is:

1)h=(1/2)*root(3)*a

2) If we resolve the equation we have

 2.1)2h=root(3)*a

 2.2)(2h/root(3))=a

3) After the replacement of each value we have that

a=2*3.32/1.73205

a=3.833 cm

And we know that the equilateral triangle has the same value for each side so a=b=c=3.833 cm

7 0
3 years ago
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