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kogti [31]
4 years ago
13

Can a supertanker float in a bathtub?

Physics
2 answers:
zhuklara [117]4 years ago
6 0
1. Has to be a very large bathtub or very, very small supertanker 2. The car hit harder because the bug is not going anywhere near the same speed as the car, therefore it is not exerting the same force. 3. It's so fast it's hard to put a number on it and and it depends on the think Es of wire, distance from wall, and which type of T.V. (because if it requires less electricity then the electrons will travel slower) 4. The ball being thrown, because when and object is thrown and then falls, it always falls at a greater speed then those just being dropped.
Ugo [173]4 years ago
5 0
I'm so glad you asked !

1).  If the bathtub is big enough to accommodate the length, width, and draft
of the ship, and the tub is full of water, then the ship floats in the tub.
(Strange as it may seem, the same can be said of the planet Saturn.)

2).  Momentum is conserved.  ===> The total momentum of (car + bug)
is the same before and after the collision.  ===> The impulse imparted
to the car is equal to the impulse imparted to the bug.  ===> F₁·t = F₂·t .
===> For every action, there is an equal and opposite reaction.
===> The force exerted on the bug is equal to the force exerted on the car.
===> The bug sustains more damage than the car does.

3).  This simple-sounding question is actually a very complicated question.
... You said "an electron".  Do you mean the same electron ?  Or do you mean
the electric current ?
... The 'drift velocity' of the same electron is only millimeters per hour.
... If you're plugged into a common AC wall socket, then a single electron is
pulled this way, then that way, 60 times a second, and never gets anywhere.
... Electric current flows by means of one electron bumping the next one,
which bumps the next one, which bumps the next one, which bumps the
next one, and so on all along the wire.  So the EFFECT shows up at the
other end of the wire much faster than any single electron gets there.
... That speed depends on the thickness and composition of the wire,
the thickness and composition of the insulation around the wire, the
distance between the two wires in the power cord, and some other things.
It can range anywhere from 45% to 99% of the speed of light.

-- If your power cord is 5 feet long and the propagation velocity is 0.99c,
then the answer to your question is  0.000 000 005 13 second.

-- If your power cord is 10 feet long and the propagation velocity is 0.45c,
then the answer to your question is   0.000 000 022 6 second.

The actual situation is somewhere in that range.

4).  When you toss a ball or a stone straight up, it goes up for a while
as it slows down, then turns around, then falls for a while as it speeds up. 
It's fairly easy to prove that it returns to your hand with the same speed
as you tossed it.
So if you toss two stones, with the same speed, from the same height,
one up and one down, then the one that went up and came back has the
same speed as it passes your hand going down. 
They both hit the ground with the same speed.
But there IS one difference:  The one you tossed UP hits the ground LATER !
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D) all of the above is the answer
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I WILLLL GIVEEEEEE YOU BRAINLYYYYY!!!!!!!!!! Write your own definition of Scientific Law and a Scientific Theory in your own wor
svp [43]

Explanation:

scientific laws are totally fixed.

sciebtific theories are not totally accurate.

5 0
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A negative charge feels a force when stationary in an electric field. moving parallel to an electric field. moving parallel to a
Yuki888 [10]

Answer:

<u>stationary in an electric field. </u>

<u>moving perpendicular to a magnetic field.</u>

<u>moving perpendicular to an electric</u> <u>field.</u>

Explanation:

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However, the correct answer in the question above, would be:

<u>"stationary in an electric field". </u>

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<u>"moving perpendicular to an electric</u> <u>field".</u>

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3 years ago
What does deposition mean in a sedimentary formation
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Answer:

Sedimentary rocks are types of rock that are formed by the deposition and subsequent cementation of that material at the Earth's surface and within bodies of water. Deposition means that all the sediments, soil, and rocks are all compressed (tightly pressed into each other) and create sedimentary rocks.

I hope this helps! :)
4 0
3 years ago
A 99.5 N grocery cart is pushed 12.9 m along an aisle by a shopper who exerts a constant horizontal force of 34.6 N. The acceler
Romashka [77]

1) 9.4 m/s

First of all, we can calculate the work done by the horizontal force, given by

W = Fd

where

F = 34.6 N is the magnitude of the force

d = 12.9 m is the displacement of the cart

Solving ,

W = (34.6 N)(12.9 m) = 446.3 J

According to the work-energy theorem, this is also equal to the kinetic energy gained by the cart:

W=K_f - K_i

Since the cart was initially at rest, K_i = 0, so

W=K_f = \frac{1}{2}mv^2 (1)

where

m is the of the cart

v is the final speed

The mass of the cart can be found starting from its weight, F_g = 99.5 N:

m=\frac{F_g}{g}=\frac{99.5 N}{9.8 m/s^2}=10.2 kg

So solving eq.(1) for v, we find the final speed of the cart:

v=\sqrt{\frac{2W}{m}}=\sqrt{\frac{2(446.3 J)}{10.2 kg}}=9.4 m/s

2) 2.51\cdot 10^7 J

The work done on the train is given by

W = Fd

where

F is the magnitude of the force

d is the displacement of the train

In this problem,

F=4.28 \cdot 10^5 N

d=586 m

So the work done is

W=(4.28\cdot 10^5 N)(586 m)=2.51\cdot 10^7 J

3)  2.51\cdot 10^7 J

According to the work-energy theorem, the change in kinetic energy of the train is equal to the work done on it:

W=\Delta K = K_f - K_i

where

W is the work done

\Delta K is the change in kinetic energy

Therefore, the change in kinetic energy is

\Delta K = W = 2.51\cdot 10^7 J

4) 37.2 m/s

According to the work-energy theorem,

W=\Delta K = K_f - K_i

where

K_f is the final kinetic energy of the train

K_i = 0 is the initial kinetic energy of the train, which is zero since the train started from rest

Re-writing the equation,

W=K_f = \frac{1}{2}mv^2

where

m = 36300 kg is the mass of the train

v is the final speed of the train

Solving for v, we find

v=\sqrt{\frac{2W}{m}}=\sqrt{\frac{2(2.51\cdot 10^7 J)}{36300 kg}}=37.2 m/s

7 0
4 years ago
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