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anzhelika [568]

3 years ago

15

Lavel the vertex and axis of symmetry

1 answer:

Lostsunrise [7]3 years ago

3 0

The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The xx -coordinate of the vertex is the equation of the axis of symmetry of the parabola.

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The bar chart shows the number of students with each letter grade in a certain professor's math classes. Since students need at

algol13

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Since students need at least a C for the grade to transferdes that are less than C into one category instead of grouping D's and F's separately. How many ...

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3 years ago

Read 2 more answers

Vera_Pavlovna [14]

Answer:

arc AC = 111°

Step-by-step explanation:

∠APC is a central angle, so arc AC is equal to the measure of ∠APC.

∠APC and ∠BPC are supplementary. So, m∠APC + m∠BPC = 180

m∠APC + 69 = 180

m∠APC = 111

arc AC = 111°

8 0

3 years ago

Endpoint: (9,-10), midpoint: (4,8)

Alika [10]

Answer:

( -1 , 26)

Step-by-step explanation:

So since you need to find the other endpoint, you would follow these steps:

1.) $4 = \frac{9 + x}{2\\}$

2.) 8 = 9 + x ( you just multiplied the 2 to the 4 to get 8)

3.) -1 = x (just solve it like a regular equation, so just subtract 9 on both sides to get rid of it and that leaves you with -1 = x)

You took the x values of both points and put them in the equation.

And its the same for y

1.) $8 = \frac{-10 + y}{2}$

2.) 16 = -10 + y

3.) 26 = y (you added the 10 on both sides because the 10 was negative and that took the 10 out and so it left you with 26 = y)

5 0

3 years ago

Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

ad-work [718]

<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

$(3^56^8)(3^96^{10})$

Given Conner's work is:

$(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}$

We have to check if this work is correct

Yes, Conner work is correct

From given,

$(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}$

Use the following law of exponent

$a^m \times a^n = a^{m+n}$

Therefore,

$3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}$

<em><u>Given Jana's work is:</u></em>

$(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}$

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0

3 years ago

Would you rather

Elanso [62]

Answer:

i rath r buy...

the twin-pack

sunscreen

Step-by-step explanation:

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3 years ago