Question

Find the measure of each angle of a regular polygon with 8 sides

Answer 1

$\bf \textit{sum of all interior angles in a polygon}\\\\ \stackrel{sum}{\theta n}=180(n-2)\quad \begin{cases} \theta =angle~in\\ \qquad degrees\\ n=\textit{number of sides}\\ ---------\\ n=8 \end{cases}\implies \theta 8=180(8-2) \\\\\\ \theta 8=180(6)\implies \theta 8=1080\implies \theta =\cfrac{1080}{8}\implies \theta =135$