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Ksju [112]
3 years ago
12

The monthly rents for five apartments advertised in a newspaper were $670, $670, $790, $1550, and $810. Use the mean, median, mo

de, and range of the rents to answer the following question: Which value gives the average rent?
The average rent is the range, $900.

The average rent is the mode, $670.

The average rent is the mean, $898.

The average rent is the median, $790.
Mathematics
1 answer:
Zinaida [17]3 years ago
4 0
Sentences one, two, and four are incorrect because the mean is the average of a set of numbers, leaving Sentence three as the correct answer.
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Nikitich [7]

5 goes into 62 12 times with a remainder of 2. So technically 62 divided by 5 is 12.4.

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Assume that y varies directly with x. If y=1/4 when x=1/8, find x when y=3/16. Enter in any fractions using a / (e.g. "1/2" is t
wariber [46]

Answer:

3/32

Step-by-step explanation:

Whatever you do to y always happens to x right? I'm REALLY new to this question so i'm not really sure so wait for more responses if needed.

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3 years ago
Plz help me with this quick 30 points plz give me the right answers plz help me thanks
algol [13]

Answer:

1b. 2/3

2b. 4/3

3b. 3

Step-by-step explanation:

To get the answers to each of these, first change the percentage to a decimal. Then change the mixed number to an improper fraction. Then multiply.

1b.

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5/10 * 4/3

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2b.

40% * 3 1/3

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6 0
3 years ago
Difference between Arctan and arctan
kogti [31]
One with a capital A and one with a small a no other difference
6 0
4 years ago
Read 2 more answers
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
3 years ago
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