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Andre45 [30]
4 years ago
5

Can someone please explain how to solve for impulse if momentum is not given, only mass and velocity are given

Physics
1 answer:
Marta_Voda [28]4 years ago
6 0
You're in luck !  Momentum is the product of (mass) times (velocity). 

So if you're given mass and velocity, simply multiply them, and voila,
you have the momentum.
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Neglecting air resistance, what maximum height will be reached by an arrow launched straight upward with an initial speed of 35
tankabanditka [31]
The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.

The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)

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3 0
3 years ago
13. If both the directions of velocity and acceleration are negative, ...........
lawyer [7]

Answer:

B)velocity of object decreases

Explanation:

Consider the positive x axis as positive direction

Assume a body moving in negative x-axis direction

It's acceleration also alone negative x-axis direction

So according to our consideration

velocity and acceleration values are negative

That is both are towards negative x direction

But as both velocity and acceleration are in same direction, MAGNITUDE of velocity increases

But as magnitude increases in negative direction, velocity value decreases

But speed value increases(As speed is scalar and velocity is a vector)

3 0
3 years ago
Rocks from volcanoes are used by scientists to study the interior of the earth<br><br>TRUE OR FALSE​
cupoosta [38]
I think it’s false bc A volcano is not in the interior of the earth
6 0
3 years ago
Read 2 more answers
The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. Calculate the energ
olya-2409 [2.1K]

Answer: 8400 J

Explanation:

The formula referenced in the question is:

Q=m. c. \Delta T  

Where:

Q  is the thermal energy

m=100g \frac{1 kg}{1000 g}=0.1 kg is the mass  of the water sample

c=4200 \frac{J}{kg\°C}  is the specific heat capacity of  water

\Delta T=20\°C  is the variation in temperature

Solving:

Q=(0.1 kg)(4200 \frac{J}{kg\°C})(20\°C)  

Q=8400 J  This is the thermal energy released

8 0
3 years ago
Need Help.
zaharov [31]
Newton’s fifth law says so i’m sorry it’s just logic
7 0
3 years ago
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