2a) moment = 1.5P
2bi) 210*1 = 210Nm
2bii) 140N
2biii) 70 N
Answer:
Opposite to the motion of the car.
Explanation:
Please find the detailed solution below
Answer:
The amplitude ( ) of a wave is the distance from the centre line (or the still position) to the top of a crest or to the bottom of a trough . Be careful with this quantity - the centre line is not always given in a diagram.
Explanation:
Answer:
The method to determine whether a string contains a value that can be converted to a specific data type before it is converted to that data type
Explanation:
The Java string includes () method to check whether a particular sequence of character is the part of given sub string or not.
One string contain another string in Java or not.
The indexof() to check the string and substring in java
Hence java string include () method to check whether a string contains a value that can be converted to a specific data type before it is converted to that data type
Answer:
![P = 1.090\,N](https://tex.z-dn.net/?f=P%20%3D%201.090%5C%2CN)
Explanation:
The constant speed means that ball is not experimenting acceleration. This elements is modelled by using the following equation of equilibrium:
![\Sigma F = P - W + F_{D}](https://tex.z-dn.net/?f=%5CSigma%20F%20%3D%20P%20-%20W%20%2B%20F_%7BD%7D)
![\Sigma F = P - \rho \cdot V \cdot g + c\cdot v = 0](https://tex.z-dn.net/?f=%5CSigma%20F%20%3D%20P%20-%20%5Crho%20%5Ccdot%20V%20%5Ccdot%20g%20%2B%20c%5Ccdot%20v%20%3D%200)
Now, the exerted force is:
![P = \rho \cdot V \cdot g - c\cdot v](https://tex.z-dn.net/?f=P%20%3D%20%5Crho%20%5Ccdot%20V%20%5Ccdot%20g%20-%20c%5Ccdot%20v)
The volume of a sphere is:
![V = \frac{4\cdot \pi}{3}\cdot R^{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%5Ccdot%20%5Cpi%7D%7B3%7D%5Ccdot%20R%5E%7B3%7D)
![V = \frac{4\cdot \pi}{3}\cdot (0.014\,m)^{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%5Ccdot%20%5Cpi%7D%7B3%7D%5Ccdot%20%280.014%5C%2Cm%29%5E%7B3%7D)
![V = 1.149\times 10^{-5}\,m^{3}](https://tex.z-dn.net/?f=V%20%3D%201.149%5Ctimes%2010%5E%7B-5%7D%5C%2Cm%5E%7B3%7D)
Lastly, the force is calculated:
![P = (8910\,\frac{kg}{m^{3}} )\cdot (1.149\cdot 10^{-5}\,m^{3})\cdot (9.81\,\frac{m}{s^{2}} )+(0.950\,\frac{kg}{s})\cdot (0.09\,\frac{m}{s} )](https://tex.z-dn.net/?f=P%20%3D%20%288910%5C%2C%5Cfrac%7Bkg%7D%7Bm%5E%7B3%7D%7D%20%29%5Ccdot%20%281.149%5Ccdot%2010%5E%7B-5%7D%5C%2Cm%5E%7B3%7D%29%5Ccdot%20%289.81%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%29%2B%280.950%5C%2C%5Cfrac%7Bkg%7D%7Bs%7D%29%5Ccdot%20%280.09%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29)
![P = 1.090\,N](https://tex.z-dn.net/?f=P%20%3D%201.090%5C%2CN)