Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
Answer:
B. 1/2
Step-by-step explanation:
If we plug in 0 for z, we get 0/0. Apply l'Hopital's rule.
Now when we plug in 0 for z, we get:
Answer:
x=10
Step-by-step explanation:
Add 6x to both sides.
−4x+5=−35
Subtract 5 from both sides.
−4x=−40
Divide both sides by -4.
x=10
hope this helps
From the picture, we can see that ΔLSP and ΔLRN are similar, so corresponding sides are proportionate:
LN : LP = 28:12 = 7:3
Therefore, the LRN sides is 7/3 of the corresponding side of LSP.
Then, it states that the area of LSP = 50, and area of a triangle is (1/2)bh, so we set up the equation
Area of LSP = (1/2)bh = 50 ← Remember how the corresponding sides are 7/3 of LSP? Therefore, the area of LRN:
LRN = (1/2)(7b/3)(7h/3) ← Take out the 7/3 and multiply them together
= (49/9)(1/2)bh ← From LSP, we know that (1/2)bh = 50, so plug that in
= (49/9)*50 ≈ 272.222 units ²
