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3 years ago

Write an equation of the line that is the perpendicular bisector of the line segment having endpoints

Mathematics

1 answer:

Burka [1]3 years ago

3 0

Answer:

Equation of perp/bisector: y = 2

Step-by-step explanation:

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Solve the following equation for x.

Crazy boy [7]

X=(-4) or X= 4
add 112 to both sides
divide both sides by 7
then take the square root of 16

5 0

3 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

4/5=/20 math...........

Mumz [18]

Answer:

1.) 16/20

2.) 15/35

3.) 12/9

4.) 52/60

5.) 9 inches

6.) 24 centimeters

7.) 16 logs

8.) $15.40

9.) 10 miles

10.) 1.5 inches

I hope this is good enough:

7 0

3 years ago

Uhhhhhh ples help me

hoa [83]

Answer:

Approximate values according to picture:

a = 1.6, b = 4, c = 5.8

The values of given expressions:

a) a + b + c = 1.6 + 4 + 5.8 = 11.4
b) c - b + a = 5.8 - 4 + 1.6 = 3.4
c) c ÷ a + b = 5.8 ÷ 1.6 + 4 = 3.6 + 4 = 7.6 (3.6 is rounded)

4 0

3 years ago

3x-8y=24 y=x-8 Please show work

In-s [12.5K]

Answer:

3x - 8y = 24 --------(1)

y = x - 8 ---------(2)

substitute y in (1)

3x - 8( x - 8) = 24

3x - 8x + 64 = 24

-5x = 24 - 64

-5x = -40

5x = 40

x= 8

substitute x in (2)

y = 2 - 8

y = - 6

4 0

3 years ago

Read 2 more answers