For the following problem, do not use algebra. Make a guess that satisfies one or more conditions of the

Mathematics

1 answer:

Mrrafil [7]3 years ago

6 0

Answer:

47 Ducks and 7 piglets.

Step-by-step explanation:

Lets try 27 of each to start

Ducks Piglets Total legs

27 27 54 + 108 = 162. Too many

30 24 60 + 96 = 156 Too many. Increase the ducks by 10:

40 14 80 + 56 = 136.

50 4 100 + 16 = 116 This < 122 so ducks between 40 and 50..

45 9 90 + 36 = 126 Too high so increase ducks:

46 8 92 + 32 = 124 Close.

47 7 94 + 28 = 122.

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Describe and correct the error in finding the area of a sector with a radius of 6 centimeters and a central angle of 40

Jet001 [13]

Answer:

12.56

Step-by-step explanation:

Remark

Since we don't have anything other than the question, all I can do is answer the question. You are left with the task of figuring out the error.

Formula

Area = (central angle divided by 360 ) * pi r^2

Solution

Area = (40 /360) * 3.14 * 6^2

Area = 1/9 * 3.14 * 36

Area = 4 * 3.14

Area = 12.56

8 0

3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Mkey [24]

For this case, we have to:

By definition, we know:

The domain of $f (x) = \sqrt [3] {x}$ is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

$y = \sqrt [3] {x-2}$ with $x = 0$ : $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x+2}$ with $x = 0:\ y = \sqrt [3] {2}$ is also defined.

$f (x) = \sqrt {x}$ has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .