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Maurinko [17]
3 years ago
13

A train travels 98 kilometers in 4 hours, and then 99 kilometers in 1 hours. What is its average speed?

Physics
1 answer:
OverLord2011 [107]3 years ago
4 0
Distance 1=98km,time 4 hrs
distance 2=99km,time 1 hrs
total distance travelled /total time taken.
98+99=197/4+1=5
average speed=39.5km per hour
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Which characteristic do all minerals have in common?
Korolek [52]

Answer:

Five Characteristics of a Mineral

Minerals Are Natural. You must find minerals in nature; substances concocted in laboratories don't qualify. ...

Minerals Are Inorganic. ...

Minerals Are Solids. ...

Definite Chemical Composition. ...

Crystalline Structure.

These are just some examples.

Explanation:

7 0
2 years ago
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A long solenoid that has 810 turns uniformly distributed over a length of 0.380 m produces a magnetic field of magnitude 1.00 10
IRINA_888 [86]

Answer:

0.037 A

Explanation:

Magnetic field = B = 1.00 e-4 T

Length = L = 0.380 m

Number of turns = 810

B = μ₀ N I / L

⇒ Current = I = B L / μ₀ N = ( 1 e-4) ( 0.380) / (4π × 10⁻⁷)(810)

                                            = 0.037 A = 37.3 mA

5 0
3 years ago
According to newton's second law of motion,the acceleration of an object equals the net force acting on the object divided by th
Shtirlitz [24]
<span>According to newton's second law of motion,the acceleration of an object equals the net force acting on the object divided by the objects "Mass"

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5 0
3 years ago
16) A man ran a 5 mile race. The race looped around a city park and back
finlep [7]

Answer:

The man's total displacement is equal to 0.

Explanation:

Given that,

A man ran a 5 mile race. The race looped around a city park and back  to the starting line.

We need to find the total displacement of the man.

We know that,

Displacement = shortest path covered

Also,

Displacement = final position - initial position

As it reaches back to its starting line, it means, the displacement is equal to 0.

Hence, the man's total displacement is equal to 0.

3 0
3 years ago
To get off a frozen lake, a 70 kg person removes his shoe of mass 0.175 kg and throws it horizontally away from the shore at a v
MakcuM [25]

Answer:

the person will be in the shore at 10.73 minutes after launch the shoe.

Explanation:

For this we will use the law of the lineal momentum.

L_i = L_f

Also,

L = MV

where M is de mass and V the velocity.

replacing,

M_i V_i = M_{fp}V_{fp} + M_{fz}V_{fz}

wher Mi y Vi are the initial mass and velocity, Mfp y Vfp are the final mass and velocity of the person and Mfz y Vfz are the final mass and velocity of the shoe.

so, we will take the direction where be launched the shoe as negative. then:

(70)(0) = (70-0.175)(V_fp) + (0.175)(-3.2m/s)

solving for V_fp,

V_fp = \frac{(3.2)(0.175)}{69.825}

V_fp = 0.008m/s

for know when the person will be in the shore we will use the rule of three as:

1 second -------------- 0.008m

t seconds-------------- 5.15m

solving for t,

t = 5.15m/0.008m

t = 643.75 seconds = 10.73 minutes

 

3 0
3 years ago
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