Can someone help with these?

Physics

1 answer:

Slav-nsk [51]3 years ago

4 0

Twelve

For an open ended pipe, the fundamental frequency is dependent on the length of the pipe and the speed of sound. Slightly less dramatic limiting factors are the temperature and pressure.

In an open pipe column, the fundamental frequency is f1 = V_sound / (2*L) which means that the longer the pipe, the lower the frequency.

Each frequency thereafter is just a multiple of the fundamental frequency.

f2 = 2* f1

f3 = 3 * f1

fn = n*f1

But that is not really what you are being asked. You are asked about the wavelength

Start with the fundamental formula

v = f wavelenght

f = n * v/2L

v = (n*v/2L) * wavelength The "v"s cancel out

2L / n = wavelength.

Thirteen

Fourteen

If the pipe increases in length, the frequency will go down and the wavelength will go up

You might be interested in

An aluminum cylinder with a radius of 2.7 cm and a height of 67 cm is used as one leg of a workbench. The workbench pushes down

soldier1979 [14.2K]

Answer:

$1.9\times 10^{-4}$

$1.2\times 10^{-4}\ m$

Explanation:

r = Radius = 2.7 cm

F = Force = $3.2\times 10^4\ N$

A = Area = $\pi r^2$

$\sigma$ = Stress = $\frac{F}{A}$

E = Young's modulus = $7\times 10^{10}\ Pa$

$\epsilon$ = Strain

$L_0$ = Original length = 67 cm

$\Delta L$ = Change in length

Young's modulus is given by

$E=\frac{\sigma}{\epsilon}\\\Rightarrow \epsilon=\frac{\sigma}{E}\\\Rightarrow \epsilon=\frac{\frac{3.2\times 10^4}{\pi 0.027^2}}{7\times 10^{10}}\\\Rightarrow \epsilon=0.0001996=1.9\times 10^{-4}$

Strain is $1.9\times 10^{-4}$

Strain is given by

$\epsilon=\frac{\Delta L}{L_0}\\\Rightarrow \Delta L=\epsilon\times L_0\\\Rightarrow \Delta L=1.9\times 10^{-4}\times 0.67\\\Rightarrow \Delta L=0.0001273\\\Rightarrow \Delta L=1.2\times 10^{-4}\ m$