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3 years ago

Can someone help with these?

Physics

1 answer:

Slav-nsk [51]3 years ago

4 0

Twelve

For an open ended pipe, the fundamental frequency is dependent on the length of the pipe and the speed of sound. Slightly less dramatic limiting factors are the temperature and pressure.

In an open pipe column, the fundamental frequency is f1 = V_sound / (2*L) which means that the longer the pipe, the lower the frequency.

Each frequency thereafter is just a multiple of the fundamental frequency.

f2 = 2* f1

f3 = 3 * f1

fn = n*f1

But that is not really what you are being asked. You are asked about the wavelength

Start with the fundamental formula

v = f wavelenght

f = n * v/2L

v = (n*v/2L) * wavelength The "v"s cancel out

2L / n = wavelength.

Thirteen

Fourteen

If the pipe increases in length, the frequency will go down and the wavelength will go up

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Coherent light with wavelength 598 nm passes through two very narrow slits, and the interference pattern is observed on a screen

Stella [2.4K]

Answer:

1.196 μm

Explanation:

D = Screen distance = 3 m

$\lambda$ = Wavelength = 598 m

y = Distance of first-order bright fringe from the center of the central bright fringe = 4.84 mm

d = Slit distance

$tan\theta=\frac{y}{D}\\\Rightarrow \theta=tan^{-1}{\frac{y}{D}}\\\Rightarrow \theta=tan^{-1}{\frac{4.84\times 10^{-3}}{3}}\\\Rightarrow \theta=0.09243\ ^{\circ}$

$sin\theta=\frac{\lambda}{d}\\\Rightarrow d=\frac{\lambda}{sin\theta}\\\Rightarrow d=\frac{598\times 10^{-9}}{sin0.09243}\\\Rightarrow d=0.00037066\ m$

For first dark fringe

$dsin\theta=\frac{\lambda'}{2}\\\Rightarrow \lambda'=2dsin\theta\\\Rightarrow \lambda'=2\times 0.00037066\times sin0.09243\\\Rightarrow \lambda'=1.196\times 10^{-6}\\\Rightarrow \lambda'=1.196\ \mu m$

Wavelength of first-order dark fringe observed at this same point on the screen is 1.196 μm

3 0

3 years ago

A moonshiner makes the error of filling a glass jar to the brim and capping it tightly. The moonshine expands more than the glas

ohaa [14]

Answer:

ΔP = (640 N/cm^2)

Explanation:

Given:-

- The volume increase, ΔV/V0 = 4 ✕ 10^-3

- The Bulk Modulus, B = 1.6*10^9 N/m^2

Find:-

Calculate the force exerted by the moonshine per square centimeter

Solution:-

- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.

B = ΔP / [(ΔV/V)]

- Now rearrange the above relation and solve for ΔP or force per unit area.

ΔP = B* [(ΔV/V)]

- Plug in the values:

ΔP = (1.6*10^9)*(4 ✕ 10^-3)

ΔP = 6400000 N/m^2

- For unit conversion from N/m^2 to N/cm^2 we have:

ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2

ΔP = (640 N/cm^2)

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3 years ago

When summer changes to fall, what seasonal changes do plants experience? (IGNORE HIGHLIGHTED ANSWER)

lorasvet [3.4K]

Answer:

Explanation:

There is a decrease in temperature and daylight and plants produce less food.

Please mark brainliest!!

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2 years ago

A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 60.0 m/s , and it leav

nata0808 [166]

Answer:

F = -307.4 N

Explanation:

It is given that,

Mass of the baseball, m = 0.145 kg

Initial speed of the baseball, u = 60 m/s

Final speed of the baseball, $v=65\ cos(30)=56.29\ m/s$

Time of contact, $t=1.75\ ms=1.75\times 10^{-3}\ s$

(a) It is assumed to find the horizontal component of average force. It is given by :

$F=m\dfrac{v-u}{t}$

$F=0.145\dfrac{56.29-60}{1.75\times 10^{-3}}$

F = -307.4 N

So, the horizontal component of average force is 307.4 N. Hence, this is the required solution.

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3 years ago

a 4kg metal block absorbs 5000j of energy and increases to a temperature of 22°c. the metal has a specific heat capacity of 250j

e-lub [12.9K]

Answer:

17 °C

Explanation:

From specific Heat capacity.

Q = cm(t₂-t₁)................. Equation 1

Where Q = Heat absorb by the metal block, c = specific heat capacity of the metal block, m = mass of the metal block, t₂ = final temperature, t₁ = Initial temperature.

make t₁ the subject of the equation

t₁ = t₂-(Q/cm)............... Equation 2

Given: t₂ = 22 °C, Q = 5000 J, m = 4 kg, c = 250 J/kg.°c

Substitute into equation 2

t₁ = 22-[5000/(4×250)

t₁ = 22-(5000/1000)

t₁ = 22-5

t₁ = 17 °C

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2 years ago