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Elina [12.6K]
3 years ago
7

Can someone help with these?

Physics
1 answer:
Slav-nsk [51]3 years ago
4 0

Twelve

For an open ended pipe, the fundamental frequency is dependent on the length of the pipe and the speed of sound.  Slightly less dramatic limiting factors are the temperature and pressure.

In an open pipe column, the fundamental frequency is f1 = V_sound / (2*L) which means that the longer the pipe, the lower the frequency.

Each frequency thereafter is just a multiple of the fundamental frequency.

f2 = 2* f1

f3 = 3 * f1

fn = n*f1

But that is not really what you are being asked. You are asked about the wavelength

Start with the fundamental formula

v = f wavelenght

f = n * v/2L

v = (n*v/2L) * wavelength  The "v"s cancel out

2L / n = wavelength.

Thirteen

Fourteen

If the pipe increases in length, the frequency will go down and the wavelength will go up


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This is physics 11th grade and a homework question I don’t understand how to do this or what the question is asking me
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a) Frequency is the number of complete oscillations per second. Looking at the graph, there are 9 complete oscillations in 5 seconds. Thus,

Frequency = 9/5 = 1.8 oscillations per second

Frequency = 1.8 Hz

Period = 1/frequency = 1/1.8

Period = 0.056 s

b) When we differenctiate displacement with respect to time, the result is velocity.

Recall, period = 1/f = 5/9 cycles

1/4 cycle behind = 1/4 x 5/9 = 5/36

It is delayed with 5/36 sec with respect to displacement.

5/36 sec = 0.139 sec

Acceleration = first derivative of velocity = second derivative of displacement = 1/4 cycle behind velocity = 1/2 cycle behind displacement =

5/36 = 0.139 sec delayed with respect to velocity

= 5/18 = 0.2777 secs delayed with respect to displacement

Thus, the number of seconds out of phase with the displacements is 0.278 seconds

c) The formula for calculating the period of an ideal pendulum anywhere is

T = 2π√length/local gravity). We would calculate the local gravity.

From the information given,

length = 0.2

T = P = 5/9

Thus,

5/9 = 2π√0.2/local gravity)

(5/9)/2π = √0.2/local gravity

Square both sides. It becomes

[(5/9)/2π]^2 = 0.2/local gravity

local gravity = 0.2/[(5/9)/2π]^2

local gravity = 25.56 m/s^2

Thus,

acceleration due to gravity = 25.56 m/s^2

Recall, earth's gravity = 9.8 m/s^2

number of g forces = 25.56/9.8

number of g forces = 2.61

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