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3 years ago

What processes produce the different colors we see in opaque objects?

1 answer:

7 0

Answer;
Adsorption and reflection of different wavelengths of light.

Explanation;
Opaque objects are objects which we can't see through.
The color of an opaque object is the same as the light that is reflected off it.
The color of an object depends on the waves of visible light that it reflects. When the light hits an object some is absorbed (adsorption) and some reflects, for example, white is white because all the colors are reflected back, plants are green because the chlorophyll reflects the color green, making them appear green to us.

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What % of an object’s mass is below the water line if the object’s density is 0.63g/ml?

tiny-mole [99]

<u>Answer:</u>

According to the <u>Archimedes’ Principle</u>, <em>a body totally or partially immersed in a fluid at rest, experiences a vertical upward thrust equal to the mass weight of the body volume that is displaced.</em>

In this case we have an object partially immersed in water.

If we observe in <u>the image attached</u>, this object does not completely fall to the bottom because the net force acting on it is zero, this means <u>it is in equilibrium</u>.

This is due to <u>Newton’s first law of motion:</u> if a body is in equilibrium the sum of all the forces acting on it is equal to zero

$F_{total}=0$ (1)

Here, <u>the object experiences two kind of forces</u>:

A force downwards because of its weight:

Where $m$ is the mass of the object and $g$ the acceleration of gravity, which in this case (on earth) is $9.8\frac{m}{s^{2}}$

And a force applied upwards because of the buoyancy:

<h2> $F_{buoyancy}=d_{w}gV_{i}$ (3) </h2>

Where;

$d_{w}$ is the <u>density of Water</u> which is $1\frac{g}{ml}$

And $V_{i}$ is <u>the volume of the immersed part of the object</u>

Well, if the total net force exerted to the object is zero:

$F_{total}= F_{buoyancy}-W=0$ Note $W$ has a negative sign because this force is applied downwards

This means the buoyancy is equal to the weight:

<h2> $F_{buoyancy}=W$ (4) </h2>

$d_{w}gV_{i}=mg$ (5)

Dividing by $g$ in both sides:

$d_{w}V_{i}=m$ (6)

Now, <u>the density</u> of an object or fluid is the relation between the mass and the volume, in the case of the object of this problem is:

Where $V$ is the <u>Volume of the object</u>.

From (7) we can find the mass of the object:

and substitute this value in (6), in order to get a relation between the density of the object and the density of the water, as follows:

$d_{w}V_{i}= dV$

$\frac{V_{i}}{V} =\frac{d}{ d_{w}}$ (9)

Then;

This result is the same as $\frac{63}{100}$ which represents the $63\%$

Therefore the answer is:

<h2> $63\%$ of the mass of the object is below the water line or <u>immersed in water </u></h2>

5 0

3 years ago

When we will see Halley's Comet again ?

Evgen [1.6K]

We will see it again in <span>28 July 2061.</span>

8 0

4 years ago

Read 2 more answers

The density of balsa wood is 0.170 g/cm3. What is the mass if the volume is 12.0 mL?

Harlamova29_29 [7]

Answer:

<h3>The answer is 2.04 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density = 0.17 g/cm³

1 mL = 1 cm³

12 mL = 12 cm³

So we have

mass = 0.17 × 12

We have the final answer as

Hope this helps you

8 0

4 years ago

When a rocket is 4 kilometers high, it is moving vertically upward at a speed of 400 kilometers per hour. At that instant, how f

Y_Kistochka [10]

Answer:

The angle of elevation of the rocket is increasing at a rate of 48.780º per second.

Explanation:

Geometrically speaking, the distance between the rocket and the observer ( $r$ ), measured in kilometers, can be represented by a right triangle:

$r = \sqrt{x^{2}+y^{2}}$ (1)

Where:

$x$ - Horizontal distance between the rocket and the observer, measured in kilometers.

$y$ - Vertical distance between the rocket and the observer, measured in kilometers.

The angle of elevation of the rocket ( $\theta$ ), measured in sexagesimal degrees, is defined by the following trigonometric relation:

$\tan \theta = \frac{y}{x}$ (2)

If we know that $x = 5\,km$ , then the expression is:

$\tan \theta = \frac{y}{5}$

And the rate of change of this angle is determined by derivatives:

$\sec^{2}\theta \cdot \dot \theta = \frac{1}{5}\cdot \dot y$

$\frac{\dot \theta}{\cos^{2}\theta} = \frac{\dot y}{5}$

$\frac{\dot \theta\cdot (25+y^{2})}{25} = \frac{\dot y}{5}$

$\dot \theta = \frac{5\cdot \dot y}{25+y^{2}}$

Where:

$\dot \theta$ - Rate of change of the angle of elevation, measured in sexagesimal degrees.

$\dot y$ - Vertical speed of the rocket, measured in kilometers per hour.

If we know that $y = 4\,km$ and $\dot y = 400\,\frac{km}{h}$ , then the rate of change of the angle of elevation is:

$\dot \theta = 48.780\,\frac{\circ}{s}$

The angle of elevation of the rocket is increasing at a rate of 48.780º per second.

3 0

3 years ago

Help this is due today I need help

nadezda [96]

Explanation:

concave lens

hope it helps .

4 0

3 years ago