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Temka [501]
4 years ago
11

When we will see Halley's Comet again ?

Physics
2 answers:
Evgen [1.6K]4 years ago
8 0
We will see it again in <span>28 July 2061.</span>
Strike441 [17]4 years ago
6 0
Hailey's Comet comes in around 75 - 76 years. It will next appear in the night sky in the year of 2062

Hope this helps!
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A physics student wants to throw a snack to their friend. The student is on the ground while
Nataliya [291]

Answer:

The velocity 13.4 must be squared then divided by the kinetic energy to get the height of 15.7 ht

Explanation:

4 0
4 years ago
A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01x10⁵ Pa.
Cerrena [4.2K]

Answer:

\frac{1.019}{1}

Explanation:

To solve this equation we will have to consider that the bubble is filled with an Ideal Gas and as such we can use the Ideal Gas Law

PV = nRT

Where

P = Pressure

V = Volume

n = Moles

R = Ideal Gas Constant

T  = Temperature

Now since we know that the value for the temperature and moles is constant we can simply use Boyles Law for the two states

P_{1} V_{1} =P_{2} V_{2}

Let us look at the two states

State 1 (at top)

Pressure = 1.01*10^5

Volume = V_{1}

State 2 (at bottom)

Pressure = 1.01*10^5 + dgh

Where

d = Density of liquid (1000 kg/m³)

d = Acceleration due to gravity (9.8 m/s²)

d = Height of liquid (0.200 m)

Pressure = 102,962

Volume = V_{2}

Inputting these values into the Boyles Law

P_{1} V_{1} =P_{2} V_{2}\\ (101000)V_{1} = (102962)V_{2}\\ \frac{V_{1}}{V_{2}} = \frac{102962}{101000} \\  \frac{V_{1}}{V_{2}} = \frac{1.019}{1}

6 0
3 years ago
Next Page
astra-53 [7]

Answer:

D. provide the most compelling evidence of cause-and-effect relationships.

Explanation:

3 0
3 years ago
A tabletop gamer has designed a game that requires three dice to be thrown onto a tray with a measurement grid. To add an extra
Airida [17]

Answer:

The resulting coordinate is   (x,y) =  (-0.170 \ m  ,  -0.038 \ m )

Explanation:

From the question we are told that  

     The  mass of the first dice is  m_1 =  11.10 \ g

      The  mass of the second dice is  m_2  =  15.10 \ g

     The mass of the third dice is  m_3 =  18.90 \ g

     The coordinate of the first dice is (x_1, y_1) =  (0.3150\ m  ,  -0.4990 \ m  )

     The coordinate of the second dice is  (x_2,y_2) =  (-0.4050  \ m  , 0.4850 \ m  )

      The coordinate of the third dice is  (x_3 , y_3) =  (-0.1150 \ m ,  -0.1850\ m )

Generally the resulting coordinate of the center of mass of the dice in the x-axis is mathematically evaluated as

        x\ cm  =  \frac{m_1 * x_1 + m_2 * x_2 + m_3 * x_3}{m_1 + m_2 +m_3 }

i.e the summation of the moments about their x-axis divided by the magnitude of their masses

    substituting values

         x\ cm  =  \frac{11.0  * 0.3150 + 15.10 * (-0.4050) + 18.90 * (-0.1150)}{11.100 + 15.10 +18.90 }

        x\ cm  = -0.170 \ m

Generally the resulting coordinate of the center of mass of the dice in the y-axis is mathematically evaluated as

     y\ cm  =  \frac{m_1 * y_1 + m_2 * y_2 + m_3 * y_3}{m_1 + m_2 +m_3 }

     y\ cm  =  \frac{ 11.10 * (-0.4990) + (15.10) * (0.4850) + (18.90) * (-0.1850)}{ 11.10 + 15.10 +18.90 }

     y\ cm  =  -0.038 \ m

Thus the resulting coordinate is   (x,y) =  (-0.170 \ m  ,  -0.038 \ m )

4 0
3 years ago
A machine has an efficiency of 80%. How much work must be done on the machine so to make it do 50,000 J of output work?
Tamiku [17]

Work formula is Work=N∙M or Joule (J)

So you have the following given:

50 000 is the output work

.8 is the efficiency

 if you input the given = 50000 = .8*J

To get the answer just divide 50000 by .8 to get the answer.

62,500 J is the amount of work to be done.

8 0
3 years ago
Read 2 more answers
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