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4 years ago

When we will see Halley's Comet again ?

Physics

2 answers:

Evgen [1.6K]4 years ago

8 0

We will see it again in <span>28 July 2061.</span>

Strike441 [17]4 years ago

6 0

Hailey's Comet comes in around 75 - 76 years. It will next appear in the night sky in the year of 2062

Hope this helps!

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The nuclear fuel distribution in a nuclear reactor is chosen so that when in operation the wall temperature of the reactor is a

cestrela7 [59]

Answer:

Explanation:

We Often solve the the integral neutron transport equation using the collision probability (CP) method which usually requires flat flux (FF) approach. In this research, it has been carried out in the cylindrical nuclear fuel cell with the spatial of mesh with quadratic flux approach. This simply means that the neutron flux at any region of the nuclear fuel cell is forced to follow the pattern of a quadratic function.

Furthermore The mechanism may be referred to as the process of non-flat flux (NFF) approach. The parameters that calculated in this study are the k-eff and the distribution of neutron flux. The result shows that all parameters are in accordance with the result of SRAC.

8 0

4 years ago

an ice skater starts with a velocity 2.25 m/s in a 50.0 degree direction after 8.33s she is moving 4.65 m/s in a 120 degree dire

svetoff [14.1K]

Answer:

$-0.032 m/s^2$

Explanation:

To answer the question, we just need to consider the motion along the horizontal direction.

The component of the initial velocity of the ice skater along the x-direction is:

$u_x = u cos \theta =(2.25)(cos 50^{\circ})=1.45 m/s$

where u = 2.25 m/s is the initial velocity and $50^{\circ}$ is the angle.

The component of the final velocity of the ice skater along the x-direction is

$v_x = u cos \theta =(4.65)(cos 120^{\circ})=-2.33 m/s$

where u = 4.65 m/s is the final velocity and $120^{\circ}$ is the angle.

The acceleration along the x-direction is given by

$a_x=\frac{v_x-u_x}{t}$

where

t = 120 s is the time

Substituting,

$a=\frac{-2.33-(1.45)}{120}=-0.032 m/s^2$

7 0

4 years ago

A block is given a very brief push up a 20.0 degree frictionless incline to give it an initial speed of 12.0 m/s.(a) How far alo

Orlov [11]

Explanation:

(a) Net force acting on the block is as follows.

$F_{net} = -mg Sin (\theta)$

or, ma = -mg Sin (\theta)[/tex]

a = $-g Sin (\theta)$

= $-9.8 \times Sin (20^{o})$

= -3.35 $m/s^{2}$

According to the kinematic equation of motion,

$v^{2} - v^{2}_{o} = 2as$

Distance traveled by the block before stopping is as follows.

s = $\frac{v^{2} - v^{2}_{o}}{2a}$

= $\frac{(0)^{2} - (12.0)^{2}_{o}}{2 \times -3.35}$

= 21.5 m

According to the kinematic equation of motion,

v = $v_{o} + at$

0 = $12.0 m/s + \frac{1}{2} \times -3.35 m/s^{2} \times t$

$t_{1}$ = 7.16 sec

Therefore, before coming to rest the surface of the plane will slide the box till 7.16 sec.

(b) When the block is moving down the inline then net force acting on the block is as follows.

$F_{net} = -mg Sin (\theta)$

ma = $mg Sin (\theta)$

a = $g Sin (\theta)$

= $9.8 m/s^{2} \times Sin (20^{o})$

= 3.35 $m/s^{2}$

Kinematics equation of the motion is as follows.

s = $v_{o}t + \frac{1}{2}at^{2}$

21.5 m = $0 + \frac{1}{2} \times 3.35 m/s^{2} \times t^{2}$

$t_{2}$ = $\sqrt{\frac{2 \times 21.5 m}{3.35 m/s^{2}}}$

= 3.58 sec

Hence, total time taken by the block to return to its starting position is as follows.

t = $t_{1} + t_{2}$

= 7.16 sec + 3.58 sec

= 10.7 sec

Thus, we can conclude that 10.7 sec time it take to return to its starting position.

3 0

4 years ago

A length of copper wire has a resistance 29 Ω. The wire is cut into three pieces of equal length, which are then connected as pa

erik [133]

Answer:

3.222 ohms

Explanation:

If the total wire had a resistance of 29 ohms, when cut in three, each piece will have a resistance of 9.666 ohms.

As these three pieces (R1, R2 and R3) are now connected in parallel, the equivalent resistance R can be calculated using this equation:

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/9.666 + 1/9.666 + 1/9.666

1/R = 3/9.666

R = 9.666/3 = 3.222 ohms

The resistance between A and B will be 3.222 ohms

6 0

3 years ago

What is the constant snell’s law

Marat540 [252]

Snell's law is defined as “The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, for the light of a given colour and for the given pair of media”.

3 0

2 years ago