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grigory [225]
3 years ago
5

The height of a student is 150cm. What is his height in metres???! Plz ans with solution

Physics
2 answers:
Step2247 [10]3 years ago
6 0
150 cm would be 1.5 m
suter [353]3 years ago
3 0
Your Answer Would Be... 1.5 Meters.

(100 Centimeters = 1 Meter)

Glad I Could Help, And Good Luck!

~AnonymousGiantsFan~
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How and why has the Atomic Theory changed over time
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True or false: Alcohol can cause an uncontrolled ________ of the eyes, making good vision almost impossible
svetlana [45]
Twitching of the eye
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Derive a relation between time period anf frequency of a wave
Elza [17]

Answer:

The relation between frequency and time period is given by:

f = 1/T

Explanation:

In a wave motion, the particle move about the mean position with the passage of time. The particles rise to reach the highest point which is crest, and similarly falls to reach the lowest point which is trough. The cycle keeps on repeating.

The time period of the wave can be defined as the time taken to complete one such cycle. Time period is given by:

T = 2π/ω

Frequency can be defined as the number of cycles completed in unit time, which can be taken as the inverse of time period. frequency is given by

f = ω/2π

or

f = 1/T

8 0
3 years ago
Two blocks of clay, one of mass 1.00 kg and one of mass 7.00 kg, undergo a completely inelastic collision. Before the collision
RideAnS [48]

Answer:8 m/s

Explanation:

Given

m_1=1 kg

m_2=7 kg

kinetic Energy of m_1=32 J

initially m_2 is at rest and let say m_1 is moving with velocity u

kinetic Energy of m_1 is =\frac{m_1u^2}{2}=32

u^2=64

u=8 m/s

In Completely inelastic collision both mass stick together and move with common velocity

Suppose v is the common velocity

m_1u+0=(m_1+m_2)v

v=\frac{1\times 8}{1+7}=1 m/s

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7 0
3 years ago
A small charged sphere is attached to a thread and placed in an electric field. The other end of the thread is anchored so that
VMariaS [17]

Answer:

E = 9.66\times 10^{-6} N/C

direction is Horizontal

Explanation:

As we know that the string is horizontal here

so the tension force in the string is due to electrostatic force on it

now we will have

F = qE

so here the force is tension force on it

F = 6.57 \times 10^{-2} N

Q = 6.80 \times 10^3 C

now we have

6.57 \times 10^{-2} = (6.80 \times 10^3)E

E = 9.66\times 10^{-6} N/C

direction is Horizontal

4 0
3 years ago
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