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grigory [225]
3 years ago
5

The height of a student is 150cm. What is his height in metres???! Plz ans with solution

Physics
2 answers:
Step2247 [10]3 years ago
6 0
150 cm would be 1.5 m
suter [353]3 years ago
3 0
Your Answer Would Be... 1.5 Meters.

(100 Centimeters = 1 Meter)

Glad I Could Help, And Good Luck!

~AnonymousGiantsFan~
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The weight of the windsurfer is 700 newtons. Calculate the moment exerted by the windsurfer on the sailboat ​
borishaifa [10]
Hey, I think someone should help u cause I’m stuck too

Hope this helps !
6 0
2 years ago
) In the figure below, three charges K, L and M are placed at the corners of an equilateral triangle. If K and L are fixed, in w
abruzzese [7]

Answer:

B)

Explanation:

Negative (-) charge M will not move towards negative (-) charge K because, same charges will not attract each other in the given case

Negative (-) charge at the M tends to move towards positive (+) charge L in the direction of B) because opposite charges attract each other.

4 0
3 years ago
Force → F = ( − 8.0 N ) ˆ i + ( 6.0 N ) ˆ j acts on a particle with position vector → r = ( 3.0 m ) ˆ i + ( 4.0 m ) ˆ j . What a
andrey2020 [161]

Explanation:

It is given that,

Force, F=(-8\ N)i+(6\ N)j

Position vector, r=(3i+4j)\ m

(a) The torque on the particle about the origin is given by :

\tau=F\times r\\\\\tau=(-8i+6j)\times (3i+4j)\\\\\tau=(-50k)\ N-m

(b) To find the angle between r and F use dot product formula as :

F{\cdot} r=|F||r|\ \cos\theta\\\\\cos\theta=\dfrac{F{\cdot} r}{|F| |r|}\\\\\cos\theta=\dfrac{(-8i+6j){\cdot} (3i+4j)}{\sqrt{(-8)^2+6^2} \times \sqrt{3^2+4^2} }\\\\\cos\theta=\dfrac{-24+24}{\sqrt{(-8)^2+6^2} \times \sqrt{3^2+4^2} }\\\\\cos\theta=0\\\\\theta=90^{\circ}

Hence, this is the required solution.

8 0
3 years ago
Read 2 more answers
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.9 m/s. The car is a distanc
sammy [17]
If it takes t seconds to reach the car, then the distance d is 3.9t.

The bear's distance from the tourist's starting point is
6t-23

For maximum d, we set the equations equal to each other:
3.9t=6t-23
\Rightarrow -2.1t=-23
\Rightarrow t=\frac{23}{2.1}
so the distance is
d=3.9(\frac{23}{2.1})\approx42.741\ m
6 0
3 years ago
A piece of wood is floating in a tub of water. A second piece of wood rests on top of the first piece; it does NOT touch the wat
andreev551 [17]

Answer:

C)

Explanation:

The buoyancy and weight of the wood have to be equal for the system to be in equilibrium. The total mass (then, weight) of the wood is the same, so the total buoyancy has to be the same. Since buoyancy is the weight of the liquid displaced, the volume of liquid displaced will be the same in either case, which means that the water level will remain unchanged.

7 0
3 years ago
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