Answer:
P.E = 4.398 Joules.
Explanation:
Given the following data;
Spring constant, k = 71.8N/m
Displacement, x = 0.35m
To find the elastic potential energy;
The elastic potential energy of an object is given by the formula;
Substituting into the equation, we have;
Elastic potential energy = 4.398 Joules.
<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>
Answer:
Explanation:
The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :
which is known as fundamental charge.
For an object containing N excess electrons, the total charge of the object is
In this problem, the number of excess electrons in the object is:
Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:
Answer:
0.24
Explanation:
Mass of ball= 12g=0.012Kg
height of ball= 2.5m
velocity of ball before falling= 3.2m/s
potential energy of the ball=mgh= 0.012*10*2.5=0.3J
kinetic energy of the ball=0.5*m=0.5*0.012*3.2*3.2=0.6J
Loss in mechanical energy during the fall= potential energy- Kinetic energy= 0.3-0.06=0.24J
note: During the fall, the potential energy of the ball is converted to kinetic energy. the loss in energy is due to air resistance.