Answer:
41.54 grams of oxygen are required to burn 13.5 g of acetylene
Explanation:
The balanced reaction is:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- C₂H₂: 2 moles
- O₂: 5 moles
- CO₂: 4 moles
- H₂O: 2 moles
Being the molar mass of the compounds:
- C₂H₂: 26 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- C₂H₂: 2 moles* 26 g/mole= 52 grams
- O₂: 5 moles* 32 g/mole= 160 grams
- CO₂: 4 moles* 44 g/mole= 176 grams
- H₂O: 2 moles* 18 g/mole= 36 grams
You can apply the following rule of three: if by stoichiometry 52 grams of acetylene react with 160 grams of oxygen, 13.5 grams of acetylene react with how much mass of oxygen?
mass of oxygen= 41.54 grams
<u><em>41.54 grams of oxygen are required to burn 13.5 g of acetylene</em></u>
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Answer:
A. Ra, Ag, Ge, Br
Explanation:
Electronegativity by increasing order:
Radium (0.89) - Silver (1.93)- Germanium (2.01)- Bromine (2.96)
It can be any row
Explanation:
An element with a valence electrons of 3 can be in any row on the periodic table.
The rows are the horizontal arrangement of elements on the periodic table.
Elements on the same row have the same energy level.
- The periodic table rows are called periods.
- It is only in the groups that we can find such element.
- Group 3 elements have 3 valence electrons.
- Since this group cuts through all the rows, therefore, elements with 3 valence electrons can be found in any row.
learn more:
Metalloids brainly.com/question/3023499
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The answer to this question is bohr Greek
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hope this helps and sorry if this is wrong
