Answer:
Partial pressure of ammonia is 0,28.
Explanation:
For the reaction:
NH₄HS(s) ⇄ NH₃(g) + H₂S(g)
kp = 0,080 is defined as:
0,080 = P[NH₃] P[H₂S] <em>(1)</em>
Where P[NH₃] is partial pressure of NH₃
Asuming amount of NH₄HS is 1, equilibrium concentration for each compound is:
[NH₄HS] = 1 - x
P [NH₃] = x
P [H₂S] = x
Replacing in (1):
0,080 = X×X
0,080 = X²
X = 0,28 = P[NH₃]
I hope it helps
