Separation will be achieved if one component adheres to the stationary phase more than the other component does.
Condensation
..when gas cool down into liquid statr its called condensation..
The lysis reaction with the formation of two different gases, and the synthesis reaction with the reaction of hydrogen and oxygen support that water is a compound and not an element.
<h3>What is electrolysis?</h3>
The electrolysis is the analytical process for the separation or the deposition of the element in the presence of the electric field.
The passing of electric current through water results in the release of two types of gases. Thus, it can be said that water lysis or breakdown forms the release of two elements hydrogen and oxygen supporting the fact that water is a compound and not an element.
The production of water is found to be formed with the reaction of hydrogen with oxygen. Thus it supports that water is a compound and, not an element.
Learn more about electrolysis, here:
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Answer:
3.6 grams of NaCl are needed
Explanation:
Percent solution are solutions whose concentrations are expressed in percentages. The amount(either weight or volume) of a solute is expressed as a percentage of the total weight or volume of solution. Percent solutions can either be expressed as weight/volume % (wt/vol % or w/v %), weight/weight % (wt/wt % or w/w %), or volume/volume % (vol/vol % or v/v %).
A 6.0% wt/wt % solution contains 6 g of solute in 100 g of solution
Therefore, a 100 g solution contains 6.0 g of solute.
60 g of 6.0% solution will contain 60 g solution * 6.0 g solute/ 100 g solution
Mass of NaCl present = 3.6 g of NaCl
It is a simple stoichiometry problem. We have been given with balanced equation and 5.00 moles of HCl and have to calculate the moles of H2.
<span>From the balanced equation it is being clear that 2 moles of HCl are produced by 1 mole of H2. so, 1 mole of HCl will be produced by 1/2 moles of H2. So, the mole ratio of H2 and HCl is 1:2 </span>
<span>to calculate the moles of H2 for the given moles of HCl, multiply the moles of HCl by the mole ratio of H2 and HCl. </span>
<span>5.00 mole HCl x (1 mole H2/ 2 mole HCl) </span>
<span>= 2.50 mole H2 </span>
<span>so, to produce 5.00 moles of HCl, 2.50 moles of H2 are required.</span>
