<h2> <u>Rectangular</u> <u>Areas</u> <u>and</u> <u>Perimeters</u></h2>
The perimeter of a rectangle is given by:

In the problem we have these data:
- Perimeter = 6 + 2 (-2x + 20)
We replace the data in the equation of the perimeter:
<h3>6 + 2 (-2x + 20) = 2 (a - 2x + 20)
</h3>
We apply distributive property:
6 - 4x + 40 = 2a - 4x + 40
6 = 2a
6 ÷ 2 = a
3 = a
⇒ Length = 3
The area of the rectangle is given by:

We have these data:
We replace the data in the equation of the area:
<h3>Area = (3) (- 2x + 20)
</h3>
We apply the distributive property and obtain:
Area = -6x + 60
<u>The expression representing the area of the rectangle will be -6x + 60</u>
<h3>I hope I've helped!</h3>
Answer:
That is has root -12 meaning if you replace x with -12 you get 0.
5 1/4 - 2 2/3
first you find the LCM, so u can make both fractions have a like denominator. I'm thinking the LCM is 12, so:
(5 3/12) - (2 8/12)
= 63/12 - 32/12
=31/12
= 2 and 7/12
5 1/4 - 2 2/3 = 2 7/12
Answer:
There is sufficient evidence. A further explanation is provided below.
Step-by-step explanation:
According to the question,
The alternative as well as null hypothesis will be:


The test statistics will be:
⇒ 
By putting the values, we get
⇒ 
⇒ 
⇒ 
Or,
The p-value will be:
= 0.0071
i.e.,
⇒ 
Thus the above is the correct answer.