-- The object either left or crossed the starting line exactly at time=0 .
-- The object has been traveling at constant speed for all time that
we know about.
Answer:
197.5072.
Explanation:
According to the Coulomb's law, the magnitude of the electrostatic force of interaction between two charges
and
which are separated by the distance
is given by

<em>where,</em> k is the Coulomb's constant.
For the case, when,
Then, using Coulomb's law,

For the case, when,
Then, using Coulomb's law, the new electric force between the charges is given by,

I believe that it is called refracting...