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Solnce55 [7]
4 years ago
15

cup of hot chocolate has a spoon in it. How does the heat move from the hot chocolate to the metal spoon handle?

Physics
1 answer:
serg [7]4 years ago
5 0

The heat moves from the hot chocolate to the handle of the spoon by a process called thermal conduction.

It is the transfer of heat energy from one object to another when they are in contact with eachother.

Hope this answers your question.

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An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic
malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

\omega_f = \omega_0 + \alpha t

Where,

\omega_f =Final Angular Velocity

\omega_0 =Initial Angular velocity

\alpha = Angular acceleration

t = time

The relation between the tangential acceleration is given as,

a = \alpha r

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s

\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s

t = 11s

Replacing the previous equation with our values we have,

\omega_f = \omega_0 + \alpha t

9.8436 = 6.5973 + \alpha (11)

\alpha = \frac{9.8436- 6.5973}{11}

\alpha = 0.295rad/s^2

The tangential velocity then would be,

a = \alpha r

a = (0.295)(0.2)

a = 0.059m/s^2

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

\omega_f^2=\omega_0^2+2\alpha\theta

Replacing with our values and re-arrange to find \theta,

\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}

\theta = \frac{9.8436^2-6.5973^2}{2*0.295}

\theta = 90.461rad

That is equal in revolution to

\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev

The linear displacement of the system is,

x = \theta*(2\pi*r)

x = 14.397*(2\pi*\frac{0.25}{2})

x = 11.3m

5 0
3 years ago
Describe the differences and similarities between an electromotor and a generator.
Effectus [21]

Differences:

An electrical motor converts electrical energy into mechanical energy,where as a generator converts mechanical energy into electrical energy.

The principle of a electric motor if there is a change of the magnetic field across a conductor  electrons are forced to move in a direction perpendicular to the direction of the magnetic field,where as in a generator if a charge is moving in a magnetic field, a force acts on the charge in a direction perpendicular to both the velocity of the charge and the magnetic field.

similarities:

Both electric motor and generator work on the magnetic effects of electric current.

Both have the armatures to rotate the loop.

7 0
4 years ago
The acceleration of an object is inversely proportional to its mass, so if you decrease its mass while keeping the net force the
MaRussiya [10]

Answer:

True

Explanation:

Since acceleration is inversely proportional to mass, decreasing mass will make the object lighter, and thus easier to speed up. So acceleration increases as mass decreases and vice versa

5 0
2 years ago
Read 2 more answers
As temperature increases, the speed of sound: decreases increases remains the same
Verdich [7]

The answer is actually as temperature decreases the speed of sound decreases. "As temperature decreases, the speed of sound decreases. As pressure, or oceanic depth, increases, the speed of sound increases." - my book.

5 0
4 years ago
If an object has a kinetic energy of 30 j and mass of 34kg how fast is the object moving ?
Murrr4er [49]

Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.

Ek = mv^2 / 2 — multiply both sides by 2

2Ek = mv^2 — divide both sides by m

2Ek / m = V^2 — switch sides

V^2 = 2Ek / m — plug in values

V^2 = 2*30J / 34kg

V^2 = 60J/34kg

V^2 = 1.76 m/s — sqrt of both sides

V = sqrt(1.76)

V = 1.32m/s (roughly)

5 0
3 years ago
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