Answer:
The gasoline undergoes a change as it burns.
Explanation:
Just took the Unit Test review ((:
Answer:
Answer:
Number of Significant Figures: 3
The Significant Figures are 8 2 8
Explanation:
you welcome
First, we need to find out how many moles we have of
if we are given 6.35g.
We need to calculate the molar mass of the molecule:
Cu: 63.546g
N: 14.01g * 2 = 28.02g
O: 15.999g * 6 = 95.994
Add them together to get: 187.56g
So now we need to find the number of moles we are given. This can be done by setting up a multiplication equation and cancelling the units:
So now that we know the number of moles that we have, we can use the molarity equation to find the volume of the solution. The molarity equation is:
So since we are given the molarity in the equation (0.750 M), we can plug in the molarity and moles to find the volume of the solution:
So now we know that the volume is 0.04533 Liters; however the question asks for the answer in milliliters. To do this, we must multiply by 1000:
So
the volume of the solution (<em>
in mL</em>
) is 45.33 mL.
You have to use the equation q=mcΔT and solve for c to get c=q/mΔT
q=the amount of energy absorbed or released (in this case 150J)
m= the mass of the sample (in this case 10g)
c=the specific heat capacity of the sample
ΔT=the change in temperature (in this case 115°C)
when you plug everything in you should get 0.1304J/g°C
I hope this helps. Let me know if anything is unclear.
Answer:
The required volume of hexane is 0.66245 Liters.
Explanation:
Volume of octane = v=1.0 L=
Density of octane= d =
Mass of octane ,m=
Moles of octane =
Mole percentage of Hexane = 45%
Mole percentage of octane = 100% - 45% = 55%
Total moles = 11.212 mol
Moles of hexane :
Moles of hexane = 5.0454 mol
Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g
Density of the hexane,D =
Volume of hexane = V
(1 cm^3= 0.001 L)
The required volume of hexane is 0.66245 Liters.