I'm assuming you meant 10^(14) instead of 1014
if so, then the energy of one photon will be be 4.76×10^(-19) Joules
Answer:
It is in the oxidation of NADH to NAD + that lactate dehydrogenase (LDH) plays an important role. LDH catalyzes the following reaction The lactate then diffuses out of the cell and the NAD + is used to continue glycolysis.It is in this manner that the cell continues to produce energy under anerobic conditions.
Explanation:
Answer:
Mass = 57.05 g
Explanation:
Given data:
Volume of SO₂ = 20.0 L
Temperature = standard = 273 K
Pressure = standard = 1 atm
Mass of SO₂ = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
n = PV/RT
n = 1 atm × 20.0 L / 0.0821 atm.L/ mol.K× 273 k
n = 20.0 / 22.41/mol
n = 0.89 mol
Mass of SO₂:
Mass = number of moles × molar mass
Mass = 0.89 mol × 64.1 g/mol
Mass = 57.05 g
Answer:
34.23 g.
Explanation:
<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>
M = (no. of moles of solute)/(V of the solution (L)).
∴ M = (mass/molar mass)of C₁₂H₂₂O₁₁/(V of the solution (L)).
<em>∴ mass of C₁₂H₂₂O₁₁ = (M)(molar mass)(V of the solution (L)</em> = (1.0 M)((342.3 g/mol)/(0.10 L) = <em>34.23 g.</em>
<h2>Answer : Option C) Smaller volume - crowded particles - more collisions - high pressure</h2><h3>Explanation : </h3>
The kinetic molecular theory of gases explains that if there is small volume of gas there will be more crowding of the gas molecules inside the container. The crowded gas molecules will collide with each other and also with the walls of container as a result, exchange of energies will take place. Which will increase the pressure inside the container, and will raise the pressure than the initial pressure.
